Answer:
5069.04 seconds
Explanation:
The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.
It is given as:
where r = radius of orbit of Hubble Space Telescope
G = gravitational constant =
M = Mass of earth
We are given that:
r = radius of the earth + distance of HST from earth
r =
M =
Therefore, T will be:
The orbital period of the Hubble Space Telescope is 5069.04 seconds.
The two main states of mechanical energy are potential energy and kinetic energy.
The frequency of the activity <span />
Answer:
The speed of the magnetic field rising is
Explanation:
Mathematically Induced Emf is as follows
The objective of this solution is to obtain speed in Tesla per second which the same as since the unit of magnetic field B is Tesla and Time is seconds
So making the subject
N is given as 170.4 turns
Answer:
<h3>
13.28m/s</h3>
Explanation:
Complete question:
<em>A skateboarder rolls horizontally off the top of a staircase and lands at the bottom. The staircase has a horizontal length of 12.0m with a vertical drop of 2.0m. Calculate the speed of the skateboard. We can ignore air resistance.</em>
Using the following equations of motion;
Horizontal displacement
x = vt............ 1
Vertical component;
y = 1/2gt² ....... 2
v is the speed
t is the time
g is the acceleration due to gravity
Frim 1;
t = x/v ..... 3
Substitute equation 3 into 2;
From 2; y = 1/2gt² .
y = 1/2 g(x/v)²
y = 1/2 gx²/v²
y = gx²/2v²
v² = gx²/2y
v = √gx²/2y
Given;
x = 12m
y = 2m
g = 9.8m/s²
Substitute the given parameters into the give equation;
v = √(9.8)(12)²/2(4)
v = √(9.8)(144)/8
v = √1411.2/8
v = √176.4
v = 13.28m/s
Hence the approximate speed of the skateboard is 13.28m/s