The tension in the string and the acceleration must be equal for both masses. (See the free body diagrams)
A net force of 15 N is applied to a cart with a mass of 2.1 kg. a. What is the acceleration of the cart? b. How long will it tak
1 answer:
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Answer:
The gain in velocity is 0.37m/s
Explanation:
We need solve this problem though the conservation of momentum. That is,
Using the equation to find ,
Using the conservation of energy equation, we have,
Now this energy over the cannonball
The gain in velocity is 0.37m/s
Answer:
A) Concentration of A left at equilibrium of we started the reaction with [A] = 2.00 M and [B] = 2.00 M is 0.55 M.
B) Final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 M and [B] = 2.00 M is 0.90 M.
[D] = 0.90 M
Explanation:
With the first assumption that the volume of reacting mixture doesn't change throughout the reaction.
This allows us to use concentration in mol/L interchangeably with number of moles in stoichiometric calculations.
- The first attached image contains the correct question.
- The solution to part A is presented in the second attached image.
- The solution to part B is presented in the third attached image.
Answer:
cubic metre or 1e-9
Explanation:
•By division. Number of cubic millimetre divided(/) by 1000000000, equal(=): Number of cubic metre.
•By multiplication. 83 mm3(s) * 1.0E-9 = 8.3E-8 m3(s)