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Vedmedyk [2.9K]
3 years ago
8

Which of the following statements describes an anticyclone?

Physics
1 answer:
marshall27 [118]3 years ago
3 0

The answer is B high pressure.

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An object accelerates from rest to a velocity of 22 m/s over 35 m what was it’s acceleration
Zolol [24]

Answer:

2.67  seconds

i dont have an explanation

5 0
3 years ago
To simulate deafness, put ear plugs or cotton balls into your ears and put your hands over your ears to block out all sound. Des
yulyashka [42]

Just so you know, total deafness is quite different than partial deafness.

Partial deafness can be any number of things. It can be an inability to make out the contents of high notes (notes with high frequencies and few harmonics).

Partial deafness can be the inability to hear low notes. I only know one person who suffers from that.

Your response to speech is quite different. Usually you have to have people look right at you. Lip reading is an art. Most deaf people between what they partially hear and lip reading can make out about 1/2 of what is said. Guessing usually takes care of the rest. Course you can get everything all muddled by guessing.

It does change your way of life. The TV is often turned up high enough that people living 4 houses down can list to the 6 o'clock news when you do.

Music is hard to make out. The overtones are lost.

Earphones have very tinny sound.

People are not as enjoyable as they once were.

6 0
3 years ago
All ball is thrown up with a vertical velocity of 54 m/s and a horizontal velocity of 39 m/s. Calculate how many seconds it will
VikaD [51]

5.5 s

Explanation:

The time it takes for the ball to reach its maximum height can be calculated using

v_y = v_{0y} - gt \Rightarrow t = \dfrac{v_{0y}}{g}

since v_y = 0 at the top of its trajectory. Plugging in the numbers,

t = \dfrac{(54\:\text{m/s})}{(9.8\:\text{m/s}^2)} = 5.5\:\text{s}

8 0
3 years ago
An 8.0 cm object is 40.0 cm from a concave mirror that has a focal length of 10.0 cm. Its image is 16.0 cm in front of the mirro
svet-max [94.6K]
 We can rearrange the mirror equation before plugging our values in. 
1/p = 1/f - 1/q. 
1/p = 1/10cm - 1/40cm
1/p = 4/40cm - 1/40cm = 3/40cm
40cm=3p  <-- cross multiplication
13.33cm = p

Now that we have the value of p, we can plug it into the magnification equation.

M=-16/13.33=1.2
1.2=h'/8cm
9.6=h'

So the height of the image produced by the mirror is 9.6cm.
6 0
3 years ago
Picture question please answer do in 5 mins
alexandr402 [8]

Answer:

Can't see anything, please share clearly

4 0
3 years ago
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