The question provides the data in an incorrect way, but what the question is asking is for the entropy change when combining 3 moles of water at 0 °C (273.15 K) with 1 mole of water at 100 °C (373.15 K). We are told the molar heat capacity is 75.3 J/Kmol. We will be using the following formula to calculate the entropy change of each portion of water:
ΔS = nCln(T₂/T₁)
n = number of moles
C = molar heat capacity
T₂ = final temperature
T₁ = initial temperature
We can first find the equilibrium temperature of the mixture which will be the value of T₂ in each case:
[(3 moles)(273.15 K) + (1 mole)(373.15 K)]/(4 moles) = 298.15 K
Now we can find the change in entropy for the 3 moles of water heating up to 298.15 K and the 1 mole of water cooling down to 298.15 K:
ΔS = (3 moles)(75.3 J/Kmol)ln(298.15/273.15)
ΔS = 19.8 J/K
ΔS = (1 mole)(75.3 J/Kmol)ln(298.15/373.15)
ΔS = -16.9 J/K
Now we combine the entropy change of each portion of water to get the total entropy change for the system:
ΔS = 19.8 J/K + (-16.9 J/K)
ΔS = 2.9 J/K
The entropy change for combining the two temperatures of water is 2.9 J/K.
A very strong base would be bleach.
Standard enthalpy change of neutralization is the enthalpy change when 1 mole of water is produced by the reaction of an acid and a base under standard conditions.
Enthalpy change of neutralization:
- Every time enthalpy change of neutralization is calculated, one mole of water is produced.
- Heat is released when an acid and an alkali react, hence enthalpy changes of neutralization are always negative.
- The values are always quite comparable for reactions involving strong acids and alkalis, falling between -57 and -58 kJ mol-1.
- If the reaction is the same in each case of a strong acid and a strong alkali, the enthalpy change is similar.
Learn more about the Enthalpy of neutralization with the help of the given link:
brainly.com/question/15347368
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This is called a dynamic equilibrium. Therefore, the reaction is constantly going, but the amount of the reactants and products stay the same for they are both reacting at the same rate. So the answer is 4).
