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liubo4ka [24]
3 years ago
10

Identify the period and group of the element that has the electron configuration 1s22s22p63s23p3.

Chemistry
2 answers:
love history [14]3 years ago
8 0
The answer is D
The electrons are found on three shells (hence period 3) and on the third shell there are (2 + 3) electrons hence group 5A.  Also, the element is Phosphorous (P)

kicyunya [14]3 years ago
7 0
<span>Period 3, Group 5A or P... use your periodic table to count. When I first learned this I colored the S group the P group, D and F groups different colors. Group 1 A and Group 2 A are S. Groups 3A to 8A are P. The B's or transition metals are D And the lanthanide series and actinide series are F. Then count left to right. </span>
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Answer: Equilibrium constant for this reaction is 2.8 \times 10^{15}.

Explanation:

Chemical reaction equation for the formation of nickel cyanide complex is as follows.

Ni(OH)_{2}(s) + 4CN^{-}(aq) \rightleftharpoons [Ni(CN)_{4}^{2-}](aq) + 2OH^{-}(aq)

We know that,

      K = K_{f} \times K_{sp}

We are given that, K_{f} = 1.0 \times 10^{31}

and,    K_{sp} = 2.8 \times 10^{-16}

Hence, we will calculate the value of K as follows.

     K = K_{f} \times K_{sp}

     K = (1.0 \times 10^{31}) \times (2.8 \times 10^{-16})

        = 2.8 \times 10^{15}

Thus, we can conclude that equilibrium constant for this reaction is 2.8 \times 10^{15}.

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