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3 years ago

10

Identify the period and group of the element that has the electron configuration 1s22s22p63s23p3.

2 answers:

love history [14]3 years ago

8 0

The answer is D
The electrons are found on three shells (hence period 3) and on the third shell there are (2 + 3) electrons hence group 5A. Also, the element is Phosphorous (P)

kicyunya [14]3 years ago

7 0

<span>Period 3, Group 5A or P... use your periodic table to count. When I first learned this I colored the S group the P group, D and F groups different colors. Group 1 A and Group 2 A are S. Groups 3A to 8A are P. The B's or transition metals are D And the lanthanide series and actinide series are F. Then count left to right. </span>

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A brick has a mass of 4.0 kg and the Earth has a mass of 6.0 × 1027 g. Use this information to answer the questions below. Be su

Vedmedyk [2.9K]

Answer:

a) $2.4\times 10^{24} kg$ is the mass of 1 mole of bricks.

b) $2.5\times 10^3$ moles of bricks have a mass equal to the mass of the Earth.

Explanation:

a) Mass of brick = 4.0 kg

1 mole = $N_A=6.022\times 10^{23}$ particles/ atoms/molecules

Mass of $N_A$ bricks :

$=6.022\times 10^{23}\times 4.0 kg=2.4088\times 10^{24} kg\approx 2.4\times 10^{24} kg$

$2.4\times 10^{24} kg$ is the mass of 1 mole of bricks.

b)

Mass of the Earth = M = $6.0\times 10^{27} kg$

Mass of 1 mole of brick = m= $2.4\times 10^{24} kg$

Let the moles of brick with equal mass of the Earth be x.

$m\times x=M$

$x=\frac{M}{m}=\frac{6.0\times 10^{27}kg}{2.4\times 10^{24} kg}=2.5\times 10^3$

$2.5\times 10^3$ moles of bricks have a mass equal to the mass of the Earth.

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3 years ago

What amount of moles of sodium chloride is needed to prepare 1.25 L of a salt solution with a concentration of 0.750 mol/L

stellarik [79]

Answer:

Number of moles = 0.94 mol

Explanation:

Given data:

Number of moles of sodium chloride = ?

Volume of sodium chloride = 1.25 L

Concentration of solution = 0.750 mol/L

Solution:

Formula:

Concentration = number of moles/ volume in L

By putting values.

0.750 mol/L = number of mole / 1.25 L

Number of moles = 0.750 mol/L×1.25 L

Number of moles = 0.94 mol

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2 years ago