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liubo4ka [24]
3 years ago
10

Identify the period and group of the element that has the electron configuration 1s22s22p63s23p3.

Chemistry
2 answers:
love history [14]3 years ago
8 0
The answer is D
The electrons are found on three shells (hence period 3) and on the third shell there are (2 + 3) electrons hence group 5A.  Also, the element is Phosphorous (P)

kicyunya [14]3 years ago
7 0
<span>Period 3, Group 5A or P... use your periodic table to count. When I first learned this I colored the S group the P group, D and F groups different colors. Group 1 A and Group 2 A are S. Groups 3A to 8A are P. The B's or transition metals are D And the lanthanide series and actinide series are F. Then count left to right. </span>
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An aqueous solution is saturated in both potassium chlorate and carbon dioxide gas at room temperature. what happens when the so
Svetach [21]
<span>Aqueous solution is something where water is solvent. When the aqueous solution is saturated in both potassium chlorinate and carbon dioxide gas at 85C, the carbon dioxide bubbles out of the solution. The hydrophobic substances do not get dissolved in the water.</span>
3 0
3 years ago
Read 2 more answers
Determine the volume of a substance that has a density of 1.84 g/ml and a mass of 12 grams
vazorg [7]
Hey there!:

density = mass / volume

1.84 g/mL =  12 g / V

V =  12 / 1.84

V = 6.521 mL

hope this helps!
             
5 0
3 years ago
The specific heat of copper is 0.40 joules/ g °c. How much heat is needed in joules to change the temperature of a 55 gram subst
Snezhnost [94]

Answer : The amount of heat needed is, 1188 J

Explanation :

Formula used :

q=m\times c\times (T_2-T_1)

where,

q = heat needed = ?

m = mass of copper = 55 g

c = specific heat capacity of copper = 0.40J/g^oC

T_1 = initial temperature = 20.0^oC

T_2 = final temperature = 74.0^oC

Now put all the given values in the above formula, we get:

q=55g\times 0.40J/g^oC\times (74.0-20.0)^oC

q=1188J

Thus, the amount of heat needed is, 1188 J

3 0
3 years ago
Can someone please help me on the second one? I have no idea what to do.
Aleks [24]

The reaction will produce 12.1 g Ag₂S.

<em>Balanced equation</em> = 2Ag + S ⟶ Ag₂S

<em>Mass of Ag₂S</em> = 10.5 g Ag × (1 mol Ag/107.87 g Ag) × (1 mol Ag₂S/2 mol Ag)

× (247.80 g Ag₂S/1 mol Ag₂S) = 12.1 g Ag₂S

8 0
4 years ago
Coal can be used to generate hydrogen gas (a potential fuel) by thefollowing endothermic reaction.C(s) + H2O (g) &lt;==&gt; CO(g
SpyIntel [72]

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

C(s) + H_2O (g)\leftrightharpoons CO(g) + H_2(g)

Given that reaction is an endothermic reaction.

For the given options:

a)Adding more C

If the concentration of C that is the reactant is increased, so according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease of concentration of C takes place. Therefore, the equilibrium will shift in the right direction to wards the formation of hydrogen gas.

b) Adding more H_2O

If the concentration of water that is the reactant is increased, so according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease of concentration of water  takes place. Therefore, the equilibrium will shift in the right direction towards the formation of hydrogen gas.

c) Raising the temperature  of the reaction mixture

If the temperature is increased,heat of the equilibrium mixture will also increase so according to the Le-Chatlier's principle , the equilibrium will shift in the direction where decrease in heat that is decrease in temperature occurs.

As, this is an endothermic reaction, forward reaction will decrease the temperature. Hence, the equilibrium will shift in the right direction that is towards the formation of hydrogen gas.  

d) Increasing the volume  of reaction mixture

If the volume of the container is increased, the pressure will decrease according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where increase in pressure is taking place. As the number of moles of gas molecules is greater at the product side. So, the equilibrium will shift in the right direction that is towards the formation of hydrogen gas.  

e) Adding a catalyst  to reaction mixture

Role of catalyst is to attain the equilibrium quickly without disturbing the state of equilibrium. Hence, addition of catalyst will not change the equilibrium of the reaction.  

f) Adding an inert gas to reaction mixture

Adding inert gas to the mixture at constant volume will not effect the equilibrium. Hence, addition of an inert gas will not change the equilibrium of the reaction.  

6 0
3 years ago
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