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liubo4ka [24]
3 years ago
10

Identify the period and group of the element that has the electron configuration 1s22s22p63s23p3.

Chemistry
2 answers:
love history [14]3 years ago
8 0
The answer is D
The electrons are found on three shells (hence period 3) and on the third shell there are (2 + 3) electrons hence group 5A.  Also, the element is Phosphorous (P)

kicyunya [14]3 years ago
7 0
<span>Period 3, Group 5A or P... use your periodic table to count. When I first learned this I colored the S group the P group, D and F groups different colors. Group 1 A and Group 2 A are S. Groups 3A to 8A are P. The B's or transition metals are D And the lanthanide series and actinide series are F. Then count left to right. </span>
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Calculate the pH of a 0.10 M HCN solution that is 0.0070% ionized.
Anastaziya [24]

Answer:

D) 5.15

Explanation:

Step 1: Write the equation for the dissociation of HCN

HCN(aq) ⇄ H⁺(aq) + CN⁻(aq)

Step 2: Calculate [H⁺] at equilibrium

The percent of ionization (α%) is equal to the concentration of one ion at the equilibrium divided by the initial concentration of the acid times 100%.

α% = [H⁺]eq / [HCN]₀ × 100%

[H⁺]eq = α%/100% × [HCN]₀

[H⁺]eq = 0.0070%/100% × 0.10 M

[H⁺]eq = 7.0 × 10⁻⁶ M

Step 3: Calculate the pH

pH = -log [H⁺] = -log 7.0 × 10⁻⁶ = 5.15

7 0
3 years ago
A sample of granite contains various oxides of silicon, aluminum, sodium, potassium, calcium, and iron. each of these oxides giv
Julli [10]
It would have a solubility substance and surface

4 0
3 years ago
Explain using balanced chemical equations, the alkaline hydrolysis reaction of esters. ​
ser-zykov [4K]

Answer:

The alkaline hydrolysis of ester is known as saponification. When ester is heated with aqueous NaOH, sodium salt of acid and alcohol are formed.

3 0
3 years ago
An engine operates on a Carnot cycle that uses 1mole of an ideal gas as the
sattari [20]

Answer:

Step 1;

q = w = -0.52571 kJ, ΔS = 0.876 J/K

Step 2

q = 0, w = ΔU = -7.5 kJ, ΔH = -5.00574 kJ

Explanation:

The given parameters are;

P_i = 100 N·m

T_i = 327 K

P_f = 90 N·m

Step 1

For isothermal expansion, we have;

ΔU = ΔH = 0

w = n·R·T·ln(P_f/P_i) = 1 × 8.314 × 600.15 × ln(90/100) = -525.71

w ≈<em> -0.52571</em> kJ

At state 1, q = w = -0.52571 kJ

ΔS = -n·R·ln(P_f/P_i) = -1 × 8.314 × ln(90/100) ≈ 0.876

ΔS ≈ 0.876 J/K

Step 2

q = 0 for adiabatic process

ΔU = 25×(27 - 327) = -7,500

w = ΔU = <em>-7.5 kJ</em>

ΔH = ΔU + n·R·ΔT

ΔH = -7,500 + 8.3142 × 300 = -5,005.74

ΔH = ΔU = <em>-5.00574 kJ</em>

6 0
3 years ago
You have just completed assaying the change in absorbance for an enzyme. The initial absorbance was 0.022; the absorbance after
Hitman42 [59]

Answer:

The answer is 0.844/10 minutes

Explanation:

You have an enzyme that catalizes a reaction which gives a product that can be quantified by an absorbance measurement. The more reaction time, the more product quantity and higher absorbance.

The rate of the reaction is the change in products quantity per time unit. As you are using the absorbance as a measure of the product quantity, you can calculate the rate as the change in absorbance (ΔA) per time (in minutes) as follows:

rate= ΔA/time

rate= (final absorbance - initial absorbance) /minutes

rate= (0.444-0.022)/5 min

rate= 0.422/5 min

In 10 minutes will be :

rate= 0.844/10 min

Commonly, a rate is the relation between two quantities measured in different units. For example, the speed of a car is the change in meters (traveled distance) per time (m/s or km/h). For an enzyme, is the same (quantity of product/time).

4 0
3 years ago
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