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victus00 [196]
3 years ago
10

Which of the following atoms would have the longest de Broglie wavelength, if all have the same velocity?

Chemistry
1 answer:
GenaCL600 [577]3 years ago
4 0

Answer:

Li

Explanation:

The phenomenon of wave particle duality was well established by Louis deBroglie. The wavelength associated with matter waves was related to its mass and velocity as shown below;

λ= h/mv

Where;

λ= wavelength of matter waves

m= mass of the particle

v= velocity of the particle

This implies that if the velocities of all particles are the same, the wavelength of matter waves will now depend on the mass of the particle. Hence; the wavelength of a matter wave associated with a particle is inversely proportional to the magnitude of the particle's linear momentum. The longest wavelength will then be obtained from the smallest mass of matter. Hence lithium which has the smallest mass will exhibit the longest DeBroglie wavelength

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a) a = 3485 M⁻¹cm⁻¹

b) C = 0,000127 M

Explanation:

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A = a×b×C

Where A is absorbance, a is molar absorptivity, b is path length and C is concentration.

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Replacing:

0,276 = a×1,000cm×0,0000792M

<em>a = 3485 M⁻¹cm⁻¹</em>

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Replacing:

0,443 = 3485 M⁻¹cm⁻¹×1,000cm×C

<em>C = 0,000127 M </em>

<em></em>

I hope it helps!

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