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MAXImum [283]
3 years ago
9

You wash dishes for a chemistry laboratory to make extra money for laundry. You earn 12 dollars/hour, and each shift lasts 75 mi

nutes. Your laundry requires 12 quarters/load. How many loads of laundry will each shift pay for if the cost per load rises to 16 quarters?
Chemistry
2 answers:
natita [175]3 years ago
8 0

Each shift worked can pay for 3.75 loads of laundry if each load costs 16 quarters.

<h3>Further Explanation</h3>

This problem can be solved using simple dimensional analysis. The steps are:

  1. Sort the given. Identify the conversion factors or equalities that may be used. Identify what is required.
  2. Set up the dimensional analysis ensuring that units cancel out until only the desired unit is left. The equalities in the problem may be used as conversion factors.

STEP 1: Sort first the given in the problem to identify possible conversion factors to be used in the dimensional analysis.

The following equalities are given in the problem:

  • 1 shift = 75 minutes
  • 12 dollars = 1 hour
  • 1 load = 16 quarters
  • 1 dollar = 4 quarters

STEP 2: From these equalities, the following dimensional analysis can be set up:

no. \ of \ load \ = 1 \ shift \times \frac{75 \ min}{1 \ shift} \times {\frac{1 \ hr}{60 \ min} \times \frac{12 \ dollars}{1 \ hr} \times { \frac{4 \ quarters}{1 \ dollar} \times \frac{1 \ load}{16 \ quarters}

no. \ of \ load \ = 3.75 \ load

Therefore, one shift can pay for 3.75 loads of laundry.

<h3>LEARN MORE</h3>
  • Learn more about Unit Conversion brainly.com/question/1594497
  • Learn more about Dimensional Analysis brainly.com/question/8013893

Keywords: dimensional analysis, problem solving

PIT_PIT [208]3 years ago
4 0
You calculate the amount of loads of laundry as follows:

((6 x 0.25)/ load) x 10 loads = 15.00 total cost required for laundry 

<span>(6.00 / 60 min) x (75 min/shift) = 7.50 cost / shift </span>

15.00 / (7.50 / shift) = 2 loads of  laundry

Hope this answers the question.
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3 years ago
Two methanol-water mixtures are contained in separate tanks. The first mixture contains 40.0 wt% methanol and the second contain
RoseWind [281]

Answer:

M_{per}= 52.86

W_{per}=47.14

Explanation:

<u>First mixture</u>:

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m_{wat1}=200 kg * 0.6= 120 kg

<u>Second mixture</u>:

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Final mixture:

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If, the compositions are constant, the only variables are the mass of each mixture used in the final one, so there can be only one independent balance.

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Explanation:

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