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IgorC [24]
3 years ago
15

When a spring is compressed 2.50 × 10^–2 meter

Physics
1 answer:
kompoz [17]3 years ago
4 0
     The working of a spring is given by:

T_{el}= \frac{k\Delta x^2}{2}
 
     Entering the unknowns, we have:

T_{el}=\frac{k\Delta x^2}{2} \\ 1.25*10^{-2}*2*J=k(2.5*10^{-2}m)^2 \\ k= \frac{2.5*10^{-2}*J}{(2.5*10^{-2}m)^2} \\ k=40* \frac{J}{m^2} \\ k=40 \frac{N*m}{m^2}  \\ \boxed {k=40* \frac{N}{m} }
 
If you notice any mistake in my english, please let me know, because i am not native.
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