Question

A runner starts from rest and accelerates uniformly to a speed of 8.0 meters per second in 4.0 seconds. the magnitude of the acceleration of the runner is

Answer 1

The magnitude of the acceleration of the runner is given by:
$a= \frac{v_f-v_i}{t}$
where
$v_f=8.0 m/s$ is the final speed of the runner
$v_i=0$ is the initial speed of the runner
$t=4.0 s$ is the time taken

By substituting data into the equation, we find the magnitude of the acceleration:
$a= \frac{8.0 m/s -0}{4.0 s}=2 m/s^2$