The position of John at time of 4.35 s is -1.13 m
From the given chart;
- at time, t = 0, the initial velocity, u = - 2 m/s
- at time, t = 5 s, the final velocity, v = 2 m/s
The average acceleration is calculated as follows;
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The position of John at time, t = 4.35 s is calculated as follows;
Thus, the position of John at time of 4.35 s is -1.13 m
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Answer:
ΔV=0.484mV
Explanation:
The potential difference across the end of conductor that obeys Ohms law:
ΔV=IR
Where I is current
R is resistance
The resistance of a cylindrical conductor is related to its resistivity p,Length L and cross section area A
R=(pL)/A
Given data
Length L=3.87 cm =0.0387m
Diameter d=2.11 cm =0.0211 m
Current I=165 A
Resistivity of aluminum p=2.65×10⁻⁸ ohms
So
ΔV=IR
ΔV=0.484mV
No additional force is required because it's already going downhill