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Eva8 [605]
4 years ago
12

A runner starts from rest and accelerates uniformly to a speed of 8.0 meters per second in 4.0 seconds. the magnitude of the acc

eleration of the runner is
Physics
1 answer:
Paha777 [63]4 years ago
7 0
The magnitude of the acceleration of the runner is given by:
a= \frac{v_f-v_i}{t}
where
v_f=8.0 m/s is the final speed of the runner
v_i=0 is the initial speed of the runner
t=4.0 s is the time taken

By substituting data into the equation, we find the magnitude of the acceleration:
a= \frac{8.0 m/s -0}{4.0 s}=2 m/s^2
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The electric field on the surface of an irregularly shaped conductor varies from 74.0 kN/C to 14.0 kN/C.
mrs_skeptik [129]

Answer:

(a). The local surface charge density at the point on the surface where the radius of curvature of the surface is greatest is 123.9 nC/m².

(b). The local surface charge density at the point on the surface where the radius of curvature of the surface is greatest is 654.9 nC/m².

Explanation:

Given that,

Electric field E_{1}=74.0\ kN/C

Electric field E_{2}=14.0\ kN/C

When the radius of curvature is greatest, the electric field at the surface will be smaller.

Where the radius of curvature is greatest

(a). We need to calculate the local surface charge density at the point on the surface

Using formula of charge density

\sigma=\epsilon_{0}E_{2}

Put the value into the formula

\sigma=8.85\times10^{-12}\times14\times10^{3}

\sigma=1.239\times10^{-7}\ C/m^2

\sigma=123.9\times10^{-9}\ C/m^2

\sigma=123.9\ nC/m^2

The local surface charge density at the point on the surface where the radius of curvature of the surface is greatest is 123.9 nC/m².

(b). We need to calculate the local surface charge density at the point on the surface where the radius of curvature of the surface is smallest

Using formula of charge density

\sigma=\epsilon_{0}E_{1}

Put the value into the formula

\sigma=8.85\times10^{-12}\times74\times10^{3}

\sigma=6.549\times10^{-7}\ C/m^2

\sigma=654.9\times10^{-9}\ C/m^2

\sigma=654.9\ nC/m^2

The local surface charge density at the point on the surface where the radius of curvature of the surface is greatest is 654.9 nC/m².

Hence, (a). The local surface charge density at the point on the surface where the radius of curvature of the surface is greatest is 123.9 nC/m².

(b). The local surface charge density at the point on the surface where the radius of curvature of the surface is greatest is 654.9 nC/m².

7 0
3 years ago
find the gravitational force this shell exerts on a 1.60 kg point mass placed at the distance 5.01 m from the center of the shel
RideAnS [48]

The gravitational force of the shell exerts is 4.25m x 10¯¹² N.

We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses of objects. The magnitude of gravitational force can be determined as

F = G.m1.m2 / R²

where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.

From the question above, we know that

m1 = 1.6 kg

m2 = m

R = 5.01 m

By substituting the following parameters, we get

F = G.m1.m2 / R²

F = 6.674 × 10¯¹¹  . 1.6 . m / 5.01²

F = 4.25m x 10¯¹² N

where m is the mass of the shell

For more on gravitational force at: brainly.com/question/19050897

#SPJ4

7 0
1 year ago
In a collision between two objects having unequal masses, how does magnitude of the impulse imparted to the lighter object by th
olasank [31]
<span>Both objects receive the same impulse.</span>
3 0
3 years ago
There was an airplane crash, every single person on board died, but yet two people survived. How is this possible?
serg [7]
If everyone died then the too people were not on the plane they were near by when the plane crashed and were not onbard.
8 0
3 years ago
Read 2 more answers
What is the magnitude of the largest net force that can be produced by combining a force of 6.0 N
ololo11 [35]

Answer:

10N

Explanation:

The formula for calculating the resultant is expressed as;

R = √F1²+F2²

F1 and F2 are the forces

Given

F1 = 6.0N

F2 = 8.0N

R = √6²+8²

R = √36+64

R = √100

R = 10.0N

Hence the magnitude of the net force is 10N

4 0
3 years ago
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