Answer:
V₂ = -22 V
Explanation:
Electric potential and field are related
ΔV = - E d
where ΔV is the potential difference between the plates, E the electric field and d the separation between the plates
In this exercise we are given the parcionero d = 4 mm = 0.004 m, the potential of one of the plates V1 = -6V and the value of the electric field E = 4000 V / m
V₂- V₁ = - E d
V₂ = - Ed + V₁
V₂ = - 4000 0.004 + (- 6)
V₂ = -16 - 6
V₂ = -22 V
Explanation:
It is given that,
Mass of an electron, 
Initial speed of the electron, 
Final speed of the electron, 
Distance, d = 5 cm = 0.05 m
(a) The acceleration of the electron is calculated using the third equation of motion as :
Force exerted on the electron is given by :
(b) Let W is the weight of the electron. It can be calculated as :
Comparison,
Hence, this is the required solution.
Answer:
2,8
Explanation:
The first electron shell would have 2 electrons, the second shell would have 8 electrons. This is because Neon has a relative charge of 10.
Answer:
power=work done÷time taken
2×5=10
10÷10=1
ans 1J per second
