A wave's frequency is 2Hz and its wavelength is 4 m. What is the wave's speed?

is acting on an object that is constrained to move along the x-axis. If the force moves the object 3m, from the origin, what is

Snezhnost [94]

Answer:

U = - ∫ F dx

U = - 3F₀

Explanation:

Force and potential energy are related

F = $- \frac{dU}{dx}$

dU = - F dx

∫ dU = - ∫ F dx

U- U₀ = - ∫ F dx

to solve the problem we must know the form of the force, if we assume that F = F₀ and U₀ = 0 for x = 0

U = - F₀ 3

8 0

3 years ago

What is the ratio of the intensities and amplitudes of an earthquake P wave passing through the Earth and detected at two points

gavmur [86]

For both cases we will use the proportional values of the distance referring to the amplitude and intensity. Theoretically we know that the intensity is inversely proportional to the square of the distance, while the amplitude is inversely proportional to the distance, therefore,

PART A ) Intensity is inversely proportional to the square of the distance

$Intensity \propto \frac{1}{distance^2}$

Therefore the intensity of the two values would be

$\frac{I_{27}}{I_{13}} = \frac{(13km)^2}{(27km)^2}$

$\mathbf{\therefore \frac{I_{27}}{I_{13}} = 0.232 }$

PART B) Amplitude is inversely proportional to the distance

$Amplitude \propto \frac{1}{distance}$

$\frac{A_{27}}{A_{13}}= \frac{(13km)}{(27km)}$

$\mathbf{\therefore\frac{A_{27}}{A_{13}}= 0.4815}$

5 0

3 years ago

Susan competes in luge competitions during the winter months. She rides solo on a small sled 3 inches off the ground down icy sl

denis-greek [22]

The distance covered is 30.2 m

Explanation:

The motion of Cynthia is a uniformly accelerated motion (constant acceleration), so we can find the distance covered by using the following suvat equation:

$s=ut+\frac{1}{2}at^2$

where

s is the distance covered

u is the initial velocity

t is the time

a is the acceleration

In this problem,

u = 0 (since Cynthia started from rest)

t = 3.2 s

$a=5.9 m/s^2$ is her acceleration

Substituting,

$s=0+\frac{1}{2}(5.9)(3.2)^2=30.2 m$

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

8 0

3 years ago

A bicycle travels 6.10 km due east in 0.210 h, then 11.30 km at 15.0° east of north in 0.560 h, and finally another 6.10 km due

Virty [35]

Answer:

Explanation:

Given

First bicycle travels 6.10 km due to east in 0.21 h

Suppose its position vector is $r_1$

$r_1=6.10\hat{i}$

After that it travels 11.30 km at $15^{\circ}$ east of north in 0.560 h

suppose its position vector is $r_2$

$r_{2}=11.30\left ( cos15\hat{j}+sin15\hat{i}\right )$

after that he finally travel 6.10 km due to east in 0.21 h

suppose its position vector is $r_3$

$r_{3}=6.10\hat{i}$

so position of final position is given by

$r=r_1+r_{2}+r_{3}$

$\vec{r}=15.12\hat{i}+10.91\hat{j}$

$\vec{v_{avg}}=\frac{\vec{r}}{t}$

t=0.21+0.56+0.21=0.98 h

$\vec{v_{avg}}=15.42\hat{i}+11.13\hat{j}$

$|v_{avg}|=\sqrt{361.71}=19.01 km/hr$

For direction

$tan\theta =\frac{11.13}{15.42}=0.721$

$\theta =35.791^{\circ}$ w.r.t to x axis

5 0

4 years ago

Physics help!! 10pt

Butoxors [25]

<span>A. accelerate toward the more massive object is your answer. In fact, even the acceleration with accelerate, also known as the jer.k. The more massive object will pull on the smaller object and the smaller object will increase its speed towards the more massive object.

idk why jer.k is a swear</span>

7 0

3 years ago

Read 2 more answers