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2 years ago

15

I can't type, so... please make brainliest answer.

1 answer:

Damm [24]2 years ago

6 0

Im not sure because I didn’t see the passage but I feel like it would either be A or B sorry if this didn’t help at all

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How does the wavelength of a wave change when frequency decreases? when frequency increases?

Law Incorporation [45]

When the frequency decreases the wavelength is further apart. When it increases its closer together. Think about a flat line when the frequency is low the wavelengths are wider. When its a high frequency the squiggly lines on the moniter are taller and thinner so the wavelengths are not as wide and not that far from each other depending on how high the frequency is.

5 0

2 years ago

The particle in the atom with a negative charge is the ______<br> Answer here

NISA [10]

Answer:

Explanation:

The electron has a negative charge. Proton is positive and neutron is neutral.

4 0

2 years ago

Read 2 more answers

ch4aika [34]

Answer: C.

Explanation:

Just took quiz

8 0

2 years ago

A crate rests on a flatbed truck which is initially traveling at 17.9 m/s on a level road. The driver applies the brakes and the

Mamont248 [21]

Answer:

The minimum coefficient of friction required is 0.35.

Explanation:

The minimum coefficient of friction required to keep the crate from sliding can be found as follows:

$-F_{f} + F = 0$

$-F_{f} + ma = 0$

$\mu mg = ma$

$\mu = \frac{a}{g}$

Where:

μ: is the coefficient of friction

m: is the mass of the crate

g: is the gravity

a: is the acceleration of the truck

The acceleration of the truck can be found by using the following equation:

$v_{f}^{2} = v_{0}^{2} + 2ad$

$a = \frac{v_{f}^{2} - v_{0}^{2}}{2d}$

Where:

d: is the distance traveled = 46.1 m

$v_{f}$ : is the final speed of the truck = 0 (it stops)

$v_{0}$ : is the initial speed of the truck = 17.9 m/s

$a = \frac{-(17.9 m/s)^{2}}{2*46.1 m} = -3.48 m/s^{2}$

If we take the reference system on the crate, the force will be positive since the crate will feel the movement in the positive direction.

$\mu = \frac{a}{g}$

$\mu = \frac{3.48 m/s^{2}}{9.81 m/s^{2}}$

$\mu = 0.35$

Therefore, the minimum coefficient of friction required is 0.35.

I hope it helps you!

4 0

2 years ago

What is the density of a iphone with a mass of 200g and a volume of 40cm3

Leviafan [203]

Answer: 5 gm/cc

Explanation:

200 gm/40 cc
= 5 gm/cc

8 0

2 years ago