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atroni [7]
3 years ago
15

I can't type, so... please make brainliest answer.

Physics
1 answer:
Damm [24]3 years ago
6 0
Im not sure because I didn’t see the passage but I feel like it would either be A or B sorry if this didn’t help at all
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3.2 Define conservation of energy.<br>​
Free_Kalibri [48]

Answer:

A principle stating that energy cannot be created or destroyed, but can be altered from one form to another.

Explanation:

5 0
2 years ago
The apparent weight of body fully immersed in water is 30 newton and it's weight in air is 96 newton. Calculate the volume of th
Lana71 [14]

<u>Point of correction</u>

Density of water is 1000 Kg/m^{3} not 100 as provided, it may be typo

Answer:

0.0066 m^{3}

Explanation:

Buoyant force of water (Weight difference) is 96-30=66 N

Buoyancy force=\rho_w g v where \rho_w is the density of water, g is acceleration due to gravity whose value is provided as 10 m/s^{2} and v is the volume of the body

hence substituting 66 for buoyancy force, 1000 Kg/m^{3} for density of water and finding the unknown value of volume, v

66=1000*10*v

v=0.0066 m^{3}

5 0
4 years ago
Two people are pulling straight down on ropes attached to a wheel. The wheel has a radius of 2.42 m. One person pulls in a clock
natulia [17]

Answer:

69.2 Nm

Explanation:

Since torque, τ = Fd where F = force and d = distance of force from center of wheel.

The torque due to the clockwise force F' = 43.2 N at a distance d' = radius of wheel = 2.42 m (since it is at the end of the wheel) is τ' = F'd' = 43.2 N × 2.42 m = 104.544 Nm. Since this force is counterclockwise, the torque is positive. So, τ' = 104.544 Nm

The torque due to the force F" = 67.8 N at a distance d" = 0.522 m from center of wheel is τ" = F"d" = 67.8 N × 0.522 m = 35.3916 Nm. Since this force is counterclockwise, the torque is negative. So, τ" = -35.3916 Nm

The net torque on the wheel  τ =  τ' +  τ"

= 104.544 Nm + (-35.3916 Nm)

= 104.544 Nm - 35.3916 Nm

= 69.1524 Nm

≅ 69.2 Nm

4 0
3 years ago
A concrete highway is built of slabs 12 m long .How wide should be the expansion cracks between the slabs at 15 Celsius to preve
morpeh [17]

Answer:

x=4.2\ mm

Explanation:

Given:

  • length of the concrete slab, l=12\ m
  • temperature of observation, T_o=15^{\circ}C
  • we've the coefficient of linear expansion for concrete, \alpha=10^{-5}\ ^{\circ}C^{-1}
  • lower temperature limit, T_l=-30^{\circ}C
  • upper temperature limit, T_u=50^{\circ}C

<u>Change in length due to temperature can be  given as:</u>

\Delta l=l.\alpha.(T_u-T_l)

\Delta l=12\times 10^{-5}\times (50-(-30))

\Delta l=0.0096\ m=9.6\ mm

<u>Now at temperature 15°C:</u>

\Delta l'=12\times 10^{-5}\times (15-(-30))

\Delta l'=0.0054\ m=5.4\ mm

Hence the expansion crack between the slabs at this temperature must be:

x=\Delta l-\Delta l'

x=9.6-5.4

x=4.2\ mm

3 0
3 years ago
What produces light and all other electromagnetic waves?
ale4655 [162]

your answer i believe would be c because light waves, mechanical waves, exc. all carry charged particals.

5 0
4 years ago
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