<span>y=2(1/2)^x
</span>
x = 0; <span>y=2(1/2)^0 = 2(1) = 2
x = 1; </span><span>y=2(1/2)^1 = 2(1/2) = 1
answer is the last one.</span>
So the question ask to find and calculate the vector parametric equation r(t) for the line through the points P=(1,0,-2) and Q(1,5,1) for each given condition. And the possible vector parametric equation is <1,2,-2>+t/4<1,5,3>. I hope you are satisfied with my answer and feel free to ask for more
Answer:
The solution to the system of equations (x, y) = (2, 4) represents the month in which exports and imports were equal. Both were 4 in February.
Step-by-step explanation:
We're not sure what "system of equations" is being referenced here, since no equations are shown or described.
__
Perhaps your "system of equations" is ...
f(x) = some equation
g(x) = some other equation
Then the solution to this system of equation is the pair of values (x, y) that gives ...
y = f(x) = g(x)
If x represents the month number, then the solution can be read from the table:
(x, y) = (2, 4)
This is the month in which exports and imports were equal. Both numbers were 4 in February.
Answer:
(-3.5 8.5)
Step-by-step explanation:
Midpoint Formula: (
, 
)
What I did: -10 + 3 = 7, 7 / 2 = 3.5 x = 3.5 | 9 + 8 = 17, 17 / 2 = 8.5
Midpoint = (-3.5, 8.5)
