Whats is simplify 10 over 25

n Juanita's Art History class Quizzes are worth 15% of the final grade, Exams are worth 55%, Projects are worth 25%, and Attenda

kvv77 [185]

Answer:

90.75%

Step-by-step explanation:

Given;

Of the total final score;

Quizzes = 15%

Exam = 55%

Project = 25%

Attendance = 5%

Resolving the values of each section of the total score;

she had perfect attendance to class. 100% attendance;

Attendance = 5% of total score

She got extra credit on her project with a score of 26 out of 25 possible points.

Project = 26/25 × 25% = 26%

80, 85, and 96 on the first three exams,each worth 100 points;

Total exam score = 80+85+96 = 261 out of 300

Of the total score;

Exam = 261/300 × 55% = 47.85%

At mid-semester Juanita scored 119 out of 150 points on quizzes.

Quizzes = 119/150 × 15% = 11.9%

Total exam score is;

= Quizzes+exam +project+attendance

= 11.9% + 47.85% + 26% + 5%

= 90.75%

3 0

3 years ago

Which expression represents B is decreased by 25%?

emmasim [6.3K]

b is decreased by 25% which means there will be (-ve) sign.

$b - 0.25b$

<em>Option 5 is correct!!~</em>

3 0

2 years ago

A brand of grape juice that's is 25% grape juice is mixed with another brand that is 75% grape juice. The result is 7 gallons of

garri49 [273]

Answer:

5.6 gallons.

Step-by-step explanation:

If we take x gallons of 25% grape juice then it will contain $\frac{x}{4}$ gallons of pure grape juice.

Again, if we take y gallons of 75% grape juice then it will contain $\frac{3y}{4}$ gallons of pure grape juice.

If we mix them then the total volume will become x + y = 7 gallons ...... (1)

Again the mixture will become 35% juice.

So, $\frac{\frac{x}{4} +\frac{3y}{4} }{x+y} =\frac{35}{100}$

⇒ 0.25x + 0.75y = 0.35x + 0.35y

⇒0.1x = 0.4y

⇒x = 4y........ (2)

Now, solving equations (1) and (2) we get, 5y = 7, ⇒ y = 1.4 gallons

Hence, x = 4y = 5.6 gallons

Therefore, the 25% grape juice was mixed by 5.6 gallons. (Answer)

4 0

3 years ago

The set of odd numbers greater than 27

stiv31 [10]

<span>For it to be finite, it must have an upper and lower bound. It has a lower bound...but what is the highest odd number greater than 27
There's no restriction; odd numbers go on forever.</span>

5 0

3 years ago

Read 2 more answers

In March 2015, the Public Policy Institute of California (PPIC) surveyed 7525 likely voters living in California. This is the 14

lbvjy [14]

Answer:

We are confident at 99% that the difference between the two proportions is between $0.380 \leq p_{Republicans} -p_{Democrats} \leq 0.420$

Step-by-step explanation:

Part a

Data given and notation

$X_{D}=3266$ represent the number people registered as Democrats

$X_{R}=2137$ represent the number of people registered as Republicans

$n=7525$ sampleselcted

$\hat p_{D}=\frac{3266}{7525}=0.434$ represent the proportion of people registered as Democrats

$\hat p_{R}=\frac{2137}{7525}=0.284$ represent the proportion of people registered as Republicans

The standard error is given by this formula:

$SE=\sqrt{\frac{\hat p_D (1-\hat p_D)}{n_{D}}+\frac{\hat p_R (1-\hat p_R)}{n_{R}}}$

And the standard error estimated given by the problem is 0.008

Part b

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion of Democrats that approve of the way the California Legislature is handling its job

$\hat p_A =\frac{1894}{3266}=0.580$ represent the estimated proportion of Democrats that approve of the way the California Legislature is handling its job

$n_A=3266$ is the sample size for Democrats

$p_B$ represent the real population proportion of Republicans that approve of the way the California Legislature is handling its job

$\hat p_B =\frac{385}{2137}=0.180$ represent the estimated proportion of Republicans that approve of the way the California Legislature is handling its job

$n_B=2137$ is the sample for Republicans

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$(0.580-0.180) - 1.64 \sqrt{\frac{0.580(1-0.580)}{3266} +\frac{0.180(1-0.180)}{2137}}=0.380$

$(0.580-0.180) + 1.64 \sqrt{\frac{0.580(1-0.580)}{3266} +\frac{0.180(1-0.180)}{2137}}=0.420$

And the 99% confidence interval would be given (0.380;0.420).

We are confident at 99% that the difference between the two proportions is between $0.380 \leq p_{Republicans} -p_{Democrats} \leq 0.420$

5 0

3 years ago