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saw5 [17]
3 years ago
13

When web developers specify color values for text or backgrounds, they often represent RGB (red-green-blue) colors using a six-d

igit hexadecimal (base-16) value, such as #bf5700, in which the first two characters represent the red component of the color, the middle two characters represent the green component, and the final two characters represent the blue component. Each of these color components can be assigned one of 256 different values (decimal: 0 – 255, hexadecimal: 00 – ff), with lower values representing darker shades and higher values representing brighter shades.
You want to configure the text on your blog to use a slightly darker shade of purple than the one you have seen used on another website. The purple used on that site has an RGB value of #7f20ff. Which of the following RGB values would produce the darker shade of purple that you desire for your blog?
(A) #3f107f
(B) #7f60ff
(C) #aa33ff
(D) #002000
Computers and Technology
1 answer:
neonofarm [45]3 years ago
7 0

Answer: A #3f107f.

Letter B would produce a lighter blue-purple color rather than a darker shade of purple. Letter C would produce a very light purple color. Letter D would produce a Black color, making it very dark and not in the range of being purple.

Letter A would produce a darker shade of purple. As explained in the way that the RGB color hexadecimal uses, the amount of each respective color is 2 digits for each color Red, Green, Blue respectively.  By reducing the amount of each color in the RGB mode, the output will become a darker shade as the RGB mode is an ADDITITIVE type of color mode.

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Read 2 more answers
Write a do-while loop that continues to prompt a user to enter a number less than 100, until the entered number is actually less
Ad libitum [116K]

Answer:

#include<iostream>//library inclusion

using namespace std;

int main()

{

int userInput;

do//start of do while loop

{

 cout << "Enter a number less than a 100" << endl;

 cin >> userInput;

 if (userInput < 100) //condition

 {

  cout << "YOu entered less than a hundred: " << userInput << endl;

 }

 else

 {

  cout << "your number is greater than 100" << endl;

 }

} while (userInput > 100);//condition for do while

return 0;//termination of int main

}

Explanation:

The program has been commented for you. The do-while loop enters the first loop regardless of the condition. Then after the first iteration, it checks for the condition. If the condition is being met, it will iterate through, again. Otherwise it will break out of the loop and land on the "return 0;" line. Which also happens to be the termination of the program in this case. The if-else condition is used for the user to see when prompted.

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