What does 6•7-27•9+64=

Mathematics

1 answer:

Natali [406]2 years ago

4 0

Hi!

$6*7-27*9+64$

$42-27*9+64$

$42-243+64$

$Answer---->=-137$

Explanation: <u><em>This question is super super easy to me. This question is about how to use their order of operations the math problems. First you had to used PEMDAS stands for P-Parenthesis first, E-Exponents second, M-Multiply third, D-Divide fourth, A-Add fifth, and S-Subtract sixth. Then multiply and divide from left to right with 6*7=42. Then 27*9=243,42-243+64, and add or subtract from left to right with 42-243+64=-137 is the right answer. Hope this helps! And thank you for posting your question at here on Brainly. And have a great day. -Charlie</em></u>

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Help! How would I solve this trig identity?

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Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

$sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}$

Then the identity can be rewritten as:

$sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\$

Now we can multiply both sides by cos⁴(x) to get:

$\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)$