If there are 4 marbles left over each time, then we can forget about them for now.
So the question is, what is the smallest number than can be divided into 6,7 and 8?
the numbers have only one non-1 divisor in common: both 6 and 8 are divisible by 3.
so for our purposes we can "delete" one 2 and ask:
what is the smallest number than can be divided into 3,7 and 8 ?
There are no more divisors in common, so we just have to multiply them: 3*7*8=21*8=168
and the 4 marbles "extra"? We add them to this sum.
the the smallest possible number in the box is 168+4=172.
Answer: 8%
Step-by-step explanation:
Answerddsadasd
Step-by-step explanation:
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If we look at the series, one third of the current term gives the numerical value of the next term.
If we need to express it algebraically, we can write the following equation.
Therefore, our common multiplier can be found as follows. Because this sequence is a geometric sequence.
In geometric sequences, any term can be written in terms of the first term. Below is an example.
Since we know the numerical values of the first term and the common factor of the series, we can easily find the seventh term.
Answer: D 2/3
Step-by-step explanation:
Just look at the picture and each person should get two pieces.
