A kite has 2 short sides and 2 long sides. The 2 short sides are equal. The 2 long sides are also equal. This means that the other short side is 16cm. And the remaining longer sides can be found like this:
let's pretend *y* is the long side
2*y = 70 - 16 - 16. (two of the long sides = 70 - short side - another short side)
so use algebra to find y.
2*y = 38
y = 19 so the long sides are both 19cm each
Your final answer: 16cm, 19cm, 19cm
Please see the <em>blue</em> curve of the image attached below to know the graph of the function g(x) = (1/3) · 2ˣ.
<h3>How to graph a transformed function</h3>
Herein we have an <em>original</em> function f(x). The <em>transformed</em> function g(x) is the result of <em>compressing</em> f(x) by 1/3. Then, we find that g(x) = (1/3) · 2ˣ. Lastly, we graph both function on a <em>Cartesian</em> plane with the help of a <em>graphing</em> tool.
The result is attached below. Please notice that the <em>original</em> function f(x) is represented by the red curve, while the <em>transformed</em> function g(x) is represented by the blue curve.
To learn more on functions: brainly.com/question/12431044
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Answer:
s=13
Step-by-step explanation:

When two triangles<span> are </span>congruent<span> they will have exactly the same three sides and exactly the same three angles. The equal sides and angles may not be in the same position (if there is a turn or a flip), but they are there</span>
The solution is:A mole of gas occupies 22.4 L A liter is 1000 cubic centimeters because 1 cubic centimeter = 1 mL
One Helium molecule (essentially one helium atom) has atomic mass 4 g/mol So for every 22400 cubic centimeters of volume, we have 4 grams of helium Density of helium = 4g / 22400 cm^3 = 1g / 5600 cm^3
Volume of a sphere = (4/3)(pi)r^3 Volume of the outside sphere (the entire sphere) is (4/3)(pi)(R+T)^3 Volume of the inside sphere (the hollow region) is (4/3)(pi)R^3
The difference for the volume of silver. (4/3)(pi)(R+T)^3 - (4/3)(pi)R^3 = (4/3)(pi)(3R^2T + 3RT^2 + T^3)
The density of silver is 10.5g/cm^3
So the mass of the silver is computed by:10.5*(4/3)(pi)(3R^2T + 3RT^2 + T^3) = (14*pi)(3R^2T + 3RT^2 + T^3) = (14pi)T(3R^2 + 3RT + T^2)
Now for the mass of helium: volume x density = (4/3)(pi)R^3 (1/5600) = (pi/4200)R^3
Set the two masses equal: (pi/4200)R^3 = (14pi)T(3R^2 + 3RT + T^2) R^3 = 58800*T(3R^2 + 3RT + T^2) R / T = 58800*(3R^2 + 3RT + T^2) / R^2 = 58800*( 3+T/R^2+(T/R)^2)
then solve for xx = T / R 1/x = 58800*( 3+x/R+x^2) 1/58800 = x (3 + x/R + x^2) 1/58800 = 3x + x^3 x^3 + 3x - 1/58800= 0 x = ~ 5.66893x10^(-6)