width= 7m
Step-by-step explanation:
Area= L×W
L= (x+8)m
W=8m
105m²= (x+8)m × (x)m
105m²= x² + 8x
-x² - 8x + 105= 0
(x-7) (x+15) = 0
x= 7 x= -15
x=width = 7m
Since the values are the same on both sides the matrix value is a=1
Let's call the 13¢ stamps a and the 18¢ stamps b:
a+b = 42 and therefore a= 42-b (formula 1)
0.13a+0.18b= 6.66 In this formula, substitute the value of a according to formula 1:
0.13(42-b)+0.18b= 6.66 Multiply on the left to get rid of the parenthesis:
5.46-0.13b+0.18b= 6.66 Subtract 5.46 from both sides:
-0.13b+0.18b= 1.20 Add on the left:
0.05b= 1.20 Divide both sides by 0.05
b= 24 You have 24 18¢ stamps and:
42-24= 18 13¢ stamps
Check: (24 x 0.18) + (18 x 0.13)= 6.66 Correct.
Answer:
Step-by-step explanation:
Note that this function is not defined at x = 0; it does have a vertical asymptote which is the line x = 0, as well as a horiz. asymptote which is the line y = 0. This function is odd because the power of x is -1 (a negative odd number). Half the graph appears in Quadrant I: (1, 1), (2, 1/2), (3, 1/3), etc.
The other half is the reflection of the Quadrant I part in the origin, and this is because the function is odd.
Answer:
\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left[-10-\left(-6\right)\right]}{\left[4+5\right]\div \left[4^2\:−\:3^2\left(4−3\right)−8\right]+12}
Step-by-step explanation:
\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{4+5}{\left(4^2-3^2\left(4-3\right)-8\right)+12}}
