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Ainat [17]
3 years ago
12

Particle 1 of charge q1 �� ��5.00q and particle 2 of charge q2 �� ��2.00q are fixed to an x axis. (a) as a multiple of distance

l, at what coordi- nate on the axis is the net electric field of the particles zero?
Mathematics
1 answer:
Naya [18.7K]3 years ago
3 0

<span>Assuming that the particle is the 3rd particle, we know that it’s location must be beyond q2; it cannot be between q1 and q2 since both fields point the similar way in the between region (due to attraction). Choosing an arbitrary value of 1 for L, we get </span>

<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>

Rearranging to calculate for d:

<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0  
d = 2.72075922005613 
d = 0.612574113277207 </span>

<span>
We pick the value that is > q2 hence,</span>

d = 2.72075922005613*L

<span>d = 2.72*L</span>

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Name the sets of numbers to which -7/9 belongs
Arlecino [84]
Ok
the sets are
natural numbers (or counting numbers), this is like 1,2,3,4,5 etc

whole numbers, this is including 0, so 0,1,2,3,4,5,6 etc

integers, this includes the previoius set and negatives, so -3,-2,-1,0,1,2,3,4,5 etc

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5 0
3 years ago
How is the graph of y=9(3)^x-2 -6 translated from the graph of y=9(3)^x ?
USPshnik [31]
For this case we have the following function:
 y = 9 (3) ^ x
 Applying the following transformations we have:
 Horizontal translations
 Suppose that h> 0
 To graph y = f (x-h), move the graph of h units to the right.
 y = 9 (3) ^ (x-2)
 Vertical translations
 Suppose that k> 0
 To graph y = f (x) -k, move the graph of k units down.
 y = 9 (3) ^ (x-2) - 6
 Answer:
 
2 units to the right
 
6 units down
5 0
3 years ago
Javon spent %687 on pokemon cards. Energy cards cost $6 and dragon cards cost $5. If he bought a total of 127 packs then how man
pshichka [43]

Answer:

Javon purchase Energy cards = 52

Javon purchase Dragon cards = 75

Step-by-step explanation:

Given - Javon spent $687 on pokemon cards. Energy cards cost $6

             and dragon cards cost $5.

To find - If he bought a total of 127 packs then how many of each did he buy ?

Proof -

Let Javon purchase Energy cards = x

     Javon purchase Dragon cards = y

Now,

Given that he bought a total of 127 packs

⇒x + y = 127

Also,

Cost for 1 Energy card = $6

⇒Cost of x Energy cards = $ 6x

And

Cost of 1 Dragon card = $5

⇒Cost of y Dragon card = $ 5y

Now,

Given that Javon spent $687 on pokemon cards.

⇒6x + 5y = 687

∴ we get

x + y = 127                                 ..................(1)

6x + 5y = 687                            .................(2)

Multiply by 6 in equation (1) , we get

6(x + y) = 6(127)

⇒6x + 6y = 762                          .................(3)

Now,

Subtract equation (2) from equation (1) , we get

6x + 6y - (6x + 5y )= 762 - 687

⇒6x + 6y - 6x - 5y = 75

⇒y = 75

Now,

Put the value of y in equation (1), we get

x + 75 = 127

⇒x = 127 - 75

⇒x = 52

∴ we get

Javon purchase Energy cards = x = 52

Javon purchase Dragon cards = y = 75

3 0
3 years ago
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