Which linear function has a y-intercept at –3? On a coordinate plane, a line goes through points (negative 1.5, 0) and (0, 3). O
2 answers:
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Answer:
t=0
Step-by-step explanation:
r=<+1,
>
by differentiating the r vector component by component
r' = <2at, 1>
Two vector are orthogonal when the dot product between them is zero, so:
r'·r=0
<+1,
>·<2at, 1>=2
+2at+t=0
common factor
t(+2a+1)=0
Then, the only real value for t is zero.
-> t=0