Let's first say that L=W+44
and then remember that perimeter is P=2L+2W
replace the L with W+44
we then get P=2(W+44)+2W, now I'll solve it
P=2W+88+2W
P=4W+88
substitute 288 for P
288=4W+88
200=4W
50=W
so now we now how wide the court is. add 44 to find the length which gives you L=94
as always plug the numbers back into your perimeter equation to ensure L and W are correct
.558 is rounded to the nearest thousandth
You have a 300 feet side length square and you need to calculate the length of the diagonal. When you split the square along one diagonal you get triangles, so you can apply Pythagoras' Theorem, with the hypotenuse as the needed diagonal.
a²+b²=c²
300²+300²=c²
2*300²=c²
√(2*300²)=c
√(2) * √(300²)=c
√(2) * 300=c
c~424.26 ft which is the solution/option c
Answer:
the answer is differently C
Step-by-step explanation:
This time round, use SOH method (Sin angle = Opposite/Hypotenuse)
given Opposite = 7
Hypotenuse = 10
