The alloy has a density of 21.186g/cc. So for a kilogram or 1000 grams/21.186 g/cc= 45.7 cc. So the answer is 45.7 cc of the allow to make up a kilogram which shows that the density of the allow can be used to calculate the volume of a larger mass ie the kilogram.
Answer:
3.676 L.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and P are constant, and have different values of V and T:
(V₁T₂) = (V₂T₁)
V₁ = 3.5 L, T₁ = 25°C + 273 = 298 K,
V₂ = ??? L, T₂ = 40°C + 273 = 313 K,
- Applying in the above equation
(V₁T₂) = (V₂T₁)
∴ V₂ = (V₁T₂)/(T₁) = (3.5 L)(313 K)/(298 K) = 3.676 L.
Answer: The molarity of the borax solution is 0.107 M
Explanation:
The neutralization reaction is:
According to neutralization law:
where,
= basicity of 
= 2
= acidity of borax = 2
= concentration of = 1.03 M
= concentration of borax =?
= volume of = 2.07ml
= volume of borax = 20.0 ml
Now put all the given values in the above law, we get the molarity of borax:
By solving the terms, we get :
Thus the molarity of the borax solution is 0.107 M
Al 3+ ions to S 2- ions in a neutral compound is 12 oxygen
Answer:
- One mole of oxygen was used in this reaction.
- Two moles of water were produced from this reaction.
Explanation:
In addition: -<em> </em><em>T</em><em>w</em><em>o</em><em> </em><em>m</em><em>o</em><em>l</em><em>e</em><em>s</em><em> </em><em>o</em><em>f</em><em> </em><em>h</em><em>y</em><em>d</em><em>r</em><em>o</em><em>g</em><em>e</em><em>n</em><em> </em><em>w</em><em>e</em><em>r</em><em>e</em><em> </em><em>u</em><em>s</em><em>e</em><em>d</em><em>.</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>
