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Ira Lisetskai [31]
3 years ago
6

The emission spectrum of hydrogen shows discrete, bright, colored lines. Which characteristic of the Bohr model is best supporte

d by this observation?
Chemistry
2 answers:
natali 33 [55]3 years ago
7 0
The characteristic of the Bohr model that would best support his observation is this assumption: "The energy of the electron in an orbit is proportional to its distance from the nucleus. The further the electron is from the nucleus, the more energy it has." The discrete, bright, colored lines might represent the electrons and its distance from the nucleus. The lights are caused by the energy it has.
Whitepunk [10]3 years ago
3 0
<h2>Answer : Electrons cannot exist in locations other than in specific orbits.</h2><h3>Explanation : </h3>

The emission spectrum of hydrogen shows discrete, bright, colored lines. The characteristic that the Bohr model supported with observation is that electrons cannot exist in location other than in specific orbits.

According to characteristics of Bohr's atomic model;

  • The energy levels of electrons are discrete, this is the reason which is shown by hydrogen emission spectrum as discrete, bright, colored lines.
  • Also, electrons are seen to orbit around the nucleus in orbits which has a set size and energy with a defined path.
  • Electrons can jump from one energy level to another, which results after absorbing or emitting an electromagnetic radiation with a frequency ν.

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<u>Answer:</u>

<u>For a:</u> The number of moles of air present in the RV is 0.047 moles

<u>For b:</u> The number of molecules of gas is 2.83\times 10^{22}

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the number of moles, we use the equation given by ideal gas follows:

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Putting values in above equation, we get:

1.00atm\times 1.2L=n_{air}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 310K\\n_{air}=\frac{1.00\times 1.2}{0.0821\times 310}=0.047mol

Hence, the number of moles of air present in the RV is 0.047 moles

  • <u>For b:</u>

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules.

So, 0.047 moles of air will contain (0.047\times 6.022\times 10^{23})=2.83\times 10^{22} number of gas molecules.

Hence, the number of molecules of gas is 2.83\times 10^{22}

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