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svlad2 [7]
3 years ago
14

How do you write electron configurations in 2 steps?​

Chemistry
1 answer:
Galina-37 [17]3 years ago
7 0

Explanation:

Electron configuration can be carried out in two steps which can be:

  • Sublevel notation
  • Shell notations.

In the sublevel notation, the sequence of filling electrons into the orbitals of the sublevels are guided by some principles:

  • the maximum number of electrons in the orbital of sublevels are two for s-sublevel, six for p-sublevel, ten for d-sublevel and fourteen for f-sublevel. This indicates that the maximum number of electrons in an orbital is two.
  • Aufbau's prinicple states that sublevel with lower energies are filled up before those with higher energies.
  • Pauli exclusion principle states that no two electrons in an atom can have the same set of the four quantum numbers.
  • Hund's rule states that electrons go into degenerate orbitals singly first before pairing occurs.

Using the shell notation, numbers are used to denote the sum of electrons in all orbitals each energy level.

   For an atom of Be:

               Sublevel notation for the 4 electrons     1s²2s²

                        Shell notation                                    2,2

Other representation is using the electron dot structure.

Learn more

electronic configuration brainly.com/question/9616334

#learnwithBrainly

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Questions
Ulleksa [173]

Answers:

See below  

Step-by-step explanation:

1. Most food energy

(a) Pringles

Heat from Pringles + heat absorbed by water = 0

m₁ΔH  + m₂CΔT = 0

1.984ΔH + 100 × 4.184 × 18 = 0

1.984ΔH + 7530 = 0

ΔH = -7530/1.984 = -3800 J/g

(b) Cheetos

0.884ΔH + 418.4 × 13 = 0

ΔH = -5400/0.884 = -6200 J/g

Cheetos give you more food energy per gram.

(c) Snickers

Food energy = 215 Cal/28 g × 4184 J/1 Cal = 32 000 J/g

The food energy from Cheetos is much less than that from a Snickers bar

2. Experimental uncertainty

The experimental values are almost certainly too low.

Your burning food is heating up the air around it, so much of the heat of combustion is lost to the atmosphere.

3. Percent efficiency

Experimental food energy = 3800 J/g

Actual food energy = 150 Cal/28 g × 4184 J/1 Cal = 22 000 J/g

% Efficiency = Experimental value/Actual value × 100 %

                    = 3800/22 000 × 100 %

                    = 17 %

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