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suter [353]
3 years ago
15

Which sample of HCl reacts at the fastest rate with a 1.0 - gram sample of iron filling

Chemistry
1 answer:
allsm [11]3 years ago
3 0

Question:

The options are;

a. 10. mL of 1 M HCl(aq) at 10.oC

b. 10. mL of 1 M HCl(aq) at 25oC

c. 10. mL of 3 M HCl(aq) at 10.oC

d. 10. mL of 3 M HCl(aq) at 25oC

Answer:

The correct option is;

d. 10 mL of 3 M HCl(aq) at 25 °C

Explanation:

Factors that influence the rate of the reaction include;

Concentration and

Temperature

Concentration

An increase in concentration leads to a increased number of interaction among the the reacting components of HCl and iron filings such that the number of effective interaction or the rate of the reaction increases, therefore, a 10 mL 3 M HCl will react faster than a 10 mL  of 1 M HCl.

Temperature

When the temperature of the reacting HCl is increased, the energy within the reacting system increases leading to an increase in the number of high energy collisions which results in an increased reaction rate, therefore, HCl at 25 °C will react faster than HCl at 10 °C.

Hence the correct option is 10 mL of 3 M HCl(aq) at 25 °C.

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How much heat is required to warm 1.50L of water from 25.0C to 100.0C? (Assume a density of 1.0g/mL for the water.)
Masteriza [31]

<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 1.50 L = 1500 mL    (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g

To calculate the heat absorbed by the water, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

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c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(100-25)^oC=75^oC

Putting values in above equation, we get:

q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ

Hence, the amount of heat required to warm given amount of water is 470.9 kJ

6 0
3 years ago
Convert 8.876 × 10^12 m^2 to units of km^2.
Darya [45]

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Explanation:

In this problem, we need to convert 8.876 \times 10^{12}\ m^2 to km².

We know that,

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So,

8.876 \times 10^{12}\ m^2=8.876 \times 10^{12}\times 10^6\ km^2\\\\=8.876\times 10^{18}\ km^2

So, 8.876 \times 10^{12}\ m^2 is equal to 8.876\times 10^{18}\ km^2.

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Physical properties are anything you can smell, touch, or hear. They can be observed without changing.

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