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ANEK [815]
3 years ago
8

What would be the most likely charge of an ion formed from an atom with the electron configuration: 1s22s22p63s2 (2 points) +1 -

1 +2 -2
Chemistry
2 answers:
Shalnov [3]3 years ago
4 0

Answer : The correct option is, (+2)

Explanation :

The given electronic configuration is, 1s^22s^22p^63s^2

In the given electronic configuration of an atom, '3s' shell is the outermost shell in which two electrons are present. For the stable configuration, these two electrons will remove easily from the outer shell and atom will carry (+2).

Total number of electrons in the given configuration= 12 electrons

And magnesium is the element which have 12 electrons. Due to the stable electronic configuration, magnesium atom changes their electronic configuration by losing two electrons and Mg atom changes to Mg^{2+} ion.

Hence, the most likely charge of an ion formed from an atom with the given electron configuration would be, (+2)

Lady bird [3.3K]3 years ago
3 0
+2 D. because this atom is magnesium and mag. has a charge of +2
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<u>Answer:</u> The equilibrium concentration of water is 0.597 M

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aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

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The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

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1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

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