What would be the most likely charge of an ion formed from an atom with the electron configuration: 1s22s22p63s2 (2 points) +1 -
2 answers:
Answer : The correct option is, (+2)
Explanation :
The given electronic configuration is,
In the given electronic configuration of an atom, '3s' shell is the outermost shell in which two electrons are present. For the stable configuration, these two electrons will remove easily from the outer shell and atom will carry (+2).
Total number of electrons in the given configuration= 12 electrons
And magnesium is the element which have 12 electrons. Due to the stable electronic configuration, magnesium atom changes their electronic configuration by losing two electrons and atom changes to
ion.
Hence, the most likely charge of an ion formed from an atom with the given electron configuration would be, (+2)
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Answer:
⇒ We have Na2O + H2O --> NaOH. We have 2 sodiums and 2 oxygens and 2 hydrogens on the left side, but only one of each on the right side.
Sodium Oxide + Water → Sodium Hydroxide
⇒ Na2O + H2O → 2NaOH .
Sodium oxide is used in ceramics and glasses. Sodium oxide reacts exothermically with cold water to produce sodium hydroxide solution.
The molality of the solution = 17.93 m
<h3>Further explanation</h3>Given
6.00 L water with 6.00 L of ethylene glycol(ρ=1.1132 g/cm³= 1.1132 kg/L)
Required
The molality
Solution
molality = mol of solute/ 1 kg solvent
mol of solute = mol of ethylene glycol
- mass of ethylene glycol :
= volume x density
= 6 L x 1.1132 kg/L
= 6.6792 kg
= 6679.2 g
- mol of ethylene glycol (MW=62.07 g/mol)
=mass : MW
=6679.2 : 62.07
=107.608
- mass of water
6 L water = 6 kg water(ρ= 1 kg/L)
- molality