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amid [387]
3 years ago
7

Which term identifies a form of energy

Chemistry
1 answer:
34kurt3 years ago
7 0
Not sure what options I have but I have one term that identifies a form of energy which is “Energy is found in different forms, such as light, heat, sound and motion. There are many forms of energy, but they can all be put into two categories: kinetic and potential” Hope this helps.
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Time zones were adopted to fix what problem
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Time Zones were adopted to fix the time. Without the time zone, you will never know what time it is

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Is there a way u could see if the element is acid,base or salt in the periodic table?​
Vsevolod [243]

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Explanation:

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When sulfuric acid and potassium hydroxide neutralize each other to make water and potassium sulfate, how is water formed?
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It's formed by the hydrogen ion of the acid and the hydroxide of the base. 

H_{2} SO_{4} + 2KOH --\ \textgreater \  K_{2} SO_{4} + 2H_{2}O
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3 0
3 years ago
Microwave ovens heat food by creating microwave electromagnetic radiation that is absorbed by water molecules in the food.
Nikolay [14]

Explanation:

It is known that relation between heat energy and temperature change is as follows.

             Q = mC \Delta T

where, q = heat energy

            m = mass of the solution or solvent

     \Delta T = change in temperature

Hence, putting the given values into the above formula as follows.

            Q = mC \Delta T

                = 110.0 g \times \frac{315 J}{75^{o}C} \times (100 - 25)^{o}C

                = 34650 J

Now, calculate the energy of photons at wavelength 3.02 mm as follows.

             E = \frac{hc}{\lambda}

where,     h = planks constant = 6.626 \times 10^{-34} Js

                c = velocity of light = 3 \times 10^{8} m/s

            \lambda = wavelength = 3.02 mm = 3.02 \times 10^{-3} m   (as 1 m = 1000 mm)

Therefore, putting the given values into the above formula as follows.

              E = \frac{hc}{\lambda}

                 = \frac{6.626 \times 10^{-34} Js \times 3 \times 10^{8} m/s}{3.02 \times 10^{-3} m}

                = 6.58 \times 10^{-23} J

Now, the number of photons required of energy 6.58 \times 10^{-23} J/photon for the total energy of 34650 J as follows.

                E_{total} = n \times E

                     n = \frac{E_{total}}{E}

                        = \frac{34650 J}{6.58 \times 10^{-23}}

                        = 5265.95 \times 10^{23} photons

or,                     = 5.265 \times 10^{26} photons

Thus, we can conclude that the minimum number of photons present are 5.265 \times 10^{26}.

7 0
3 years ago
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