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Bingel [31]
3 years ago
13

Na+ and Cl- __________ ___________________________ Na+ and PO4 3- __________ ___________________________ Na+ and SO4 2- ________

__ ___________________________ Na+ and CO3 2- __________ ___________________________ K+ and Cl- __________ ___________________________ K+ and PO4 3- __________ ___________________________ K+ and SO4 2- __________ ___________________________ K+ and CO3 2- __________ ___________________________ Ca2+and Cl- __________ ___________________________ Ca2+ and PO4 3- __________ ___________________________ Ca2+ and SO4 2- __________ ___________________________ Ca2+ and CO3 2- __________ ___________________________ NH4 + and Cl- __________ ___________________________ NH4 + and PO4 3- __________ ___________________________ NH4 + and SO4 2- __________ ___________________________ NH4 + and CO3 2- __________ ___________________________ Fe3+ and Cl- __________ ___________________________ Fe3+ and PO4 3- __________ ___________________________ Fe3+ and SO4 2- __________ ___________________________ Fe3+ and CO3 2-
Chemistry
1 answer:
bagirrra123 [75]3 years ago
7 0

Answer:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

The cations and anions being oppositely charged attract each other through strong coloumbic forces and form an ionic bond.

(1) Sodium is carrying +1 charge called as Na^{+1} cation and chloride Cl^{-1} is an anion carrying -1 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral NaCl.

(2) Sodium is carrying +1 charge called as Na^{+1} cation and phosphate PO_4^{-3} is an anion carrying -3 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Na_3PO_4.

(3) Sodium is carrying +1 charge called as Na^{+1} cation and sulfate SO_4^{-2} is an anion carrying -2 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Na_2SO_4.

(4) Sodium is carrying +1 charge called as Na^{+1} cation and carbonate CO_3^{-2} is an anion carrying -2 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Na_2CO_3.

(5) Potassium is carrying +1 charge called as K^{+1} cation and chloride Cl^{-1} is an anion carrying -1 charge. They form KCl.

(6) Potassium is carrying +1 charge called as K^{+1} cation and phosphate PO_4^{-3} is an anion carrying -3 charge. They form K_3PO_4.

(7) Potassium is carrying +1 charge called as K^{+1} cation and sulfate SO_4^{-2} is an anion carrying -2 charge. They form K_2SO_4.

(8) Potassium is carrying +1 charge called as K^{+1} cation and carbonate CO_3^{-2} is an anion carrying -2 charge. They form K_2CO_3.

(9) Calcium is carrying +2 charge called as Ca^{+2} cation and chloride Cl^{-1} is an anion carrying -1 charge. They form CaCl_2.

(10) Calcium is carrying +2 charge called as Ca^{+2} cation and phosphate PO_4^{-3} is an anion carrying -3 charge. They form Ca_3(PO_4)_2.

(11) Calcium is carrying +2 charge called as Ca^{+2} cation and sulfate SO_4^{-2} is an anion carrying -2 charge. They form CaSO_4.

(12) Calcium is carrying +2 charge called as Ca^{+2} cation and carbonate CO_3^{-2} is an anion carrying -2 charge. They form CaCO_3.

(13) Ammonium ion is carrying +1 charge called as NH_4^{+1} cation and chloride Cl^{-1} is an anion carrying -1 charge. They form NH_4Cl.

(14) Ammonium ion is carrying +1 charge called as NH_4^{+1} cation and phosphate PO_4^{-3} is an anion carrying -3 charge. They form NH_4_3PO_4.

(15) Ammonium ion is carrying +1 charge called as NH_4^{+1} cation and sulfate SO_4^{-2} is an anion carrying -2 charge. They form NH_4_2SO_4.

(16) Ammonium ion is carrying +1 charge called as NH_4^{+1} cation and carbonate CO_3^{-2} is an anion carrying -2 charge. They form NH_4_2CO_3.

(17) Iron is carrying +3 charge called as Fe^{+3} cation and chloride Cl^{-1} is an anion carrying -1 charge. They form FeCl_3.

(18) Iron is carrying +3 charge called as Fe^{+3} cation and phosphate PO_4^{-3} is an anion carrying -3 charge. They form FePO_4.

(19) Iron is carrying +3 charge called as Fe^{+3} cation and sulfate SO_4^{-2} is an anion carrying -2 charge. They form Fe_2(SO_4)_3.

(20) Iron is carrying +3 charge called as Fe^{+3} cation and carbonate CO_3^{-2} is an anion carrying -2 charge. They form Fe_2(CO_3)_3.

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How many grams would be in 4.45 x 10^23 molecules of N203
SVETLANKA909090 [29]

Answer:

56.24g

Explanation:

To find the mass of N2O3 in 4.45 x 10^23 molecules, it must first be converted to moles by dividing the number of molecules in N2O3 by Avagadro's number (6.02 × 10^23).

number of moles in N2O3 = 4.45 x 10^23 ÷ 6.02 × 10^23

n = 4.45/6.02 × 10^(23 - 23)

n = 0.74 × 10^0

n = 0.74moles.

Using the formula below to find the mass of N2O3;

mole = mass ÷ molar mass

Molar mass of N2O3 = 14(2) + 16(3)

= 28 + 48

= 76g/mol

mass = mole × molar mass

Mass = 0.74 × 76

Mass = 56.24g

3 0
3 years ago
How many spatial orientations are available for the p sublevel
Sonja [21]

4 to 5 you are welcome

3 0
3 years ago
How many molecules of oxygen can be made from 9.52g of nickel (III) oxide?
snow_tiger [21]

Answer:

165.385 g/mol

6 0
2 years ago
a student balanced the chemical equation for the reaction of magnesium with oxygen by writing Mg + O2 ----> MgO2. What is wro
egoroff_w [7]

Answer:

Explanation:

Magnesium when it oxidizes has a valence of 2.

Oxygen, when it mixes with something, has a valence of - 2

So Mg and O2 will form something, but what? The answer is MgO

Mg + O2 ===> MgO

To balance this equation, you need 2 Magnesiums on the right and 2 Oxygens also on the right. The left will need a  two Magnesiums.

The balanced equation will be

2Mg + O2 ====> 2MgO

6 0
4 years ago
Estimate ΔG°rxn for the following reaction at 775 K. 2Hg(g) + O2(g) → 2HgO(s) ΔH°= -304.2 kJ; ΔS° = -414.2 J/K
hichkok12 [17]

Answer:

\Delta G^0_{rxn}=16.81kJ

Explanation:

Hello!

In this case, since the Gibbs free energy of any process is related with the enthalpy change, temperature and entropy change as shown below:

\Delta G^0=\Delta H^0-T\Delta S^0

For a chemical reaction it is simply modified to:

\Delta G^0_{rxn}=\Delta H^0_{rxn}-T\Delta S^0_{rxn}

Thus, since the enthalpy of reaction is given as -304.2 kJ and the entropy as -414.2 J/K (-0.4142 kJ/K), at 775 K the Gibbs free energy of reaction turns out:

\Delta G^0_{rxn}=-304kJ-775K*(-0.4142\frac{kJ}{K} )\\\\\Delta G^0_{rxn}=16.81kJ

Whose result means this is a nonspontaneous reaction.

Best regards!

3 0
3 years ago
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