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3 years ago

Will give Brainliest! if right!

1 answer:

mote1985 [20]3 years ago

8 0

The lower quartile is 21 because when you make it in order and find the median you seperate it then when you get the lower median it is 21

Your welcome

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A sundae requires 3 ice-cream scoops and 4 strawberries, and a milkshake requires 2 ice-cream scoops and 6 strawberries. Ramses

drek231 [11]

Answer:

System of inequalities:

$3x+2y \leq 25$ , $4x+6y \leq 37$

1) Maximum number of sundaes possible = 9

2) Maximum number of milkshakes possible = 6

3) Combination that uses the most of both Ice-cream and Strawberries = 7 scoop of ice-cream and 1 scoop of strawberries.

Step-by-step explanation:

Given : A sundae requires 3 ice-cream scoops and 4 strawberries, and a milkshake requires 2 ice-cream scoops and 6 strawberries.

Ramses wants to make sundaes and milkshakes with at most 25 ice-cream scoops and 37 strawberries.

Let x denote the number of sundaes he makes and y the number of milkshakes he makes.

First we represent in tabular form,

Sundae(x) Milkshake(y) Total

Ice-cream 3 2 3x+2y

Strawberries 4 6 4x+6y

→System of inequalities:

Sundaes and milkshake with at most 25 ice-cream scoops= $3x+2y \leq 25$

Sundaes and milkshakes with at most 37 strawberries = $4x+6y \leq 37$

→ Plotting the equations in the graph (figure attached)

1) Maximum number of sundaes possible:

Maximum no. of sundaes possible when y=0

From the graph y=0 at x=9.25

Therefore, Maximum number of sundaes possible is 9

2) Maximum number of milkshakes possible:

Maximum no. of milkshakes possible when x=0

From the graph x=0 at y= 6.167

Therefore, Maximum number of milkshakes possible is 6

3) Combination that uses the most of both Ice-cream and Strawberries:

Combination of both is possible there is a intersection of both the equation

From the graph intersection point is x=7.6 and y=1.1

Therefore, Combination that uses the most of both Ice-cream and Strawberries = 7 scoop of ice-cream and 1 scoop of strawberries.

5 0

3 years ago

Math question below image below

enyata [817]

Just add the x's its simple, answer is 10

3 0

3 years ago

Read 2 more answers

Find the volume of the solid that lies between planes perpendicular to the x-axis at x = pi/4 and x = 5pi/4. The cross-sections

svp [43]

Answer:

The volume of the solid = π²

Step-by-step explanation:

As per the given data of the questions,

The diameter of each disk is

D = 2 sin(x) - 2 cos(x)

So its radius is

R = sin(x) - cos(x).

The area of each disk is

$= \pi \times(sinx-cosx)^{2}$

$= \pi \times [sin^{2}(x) - 2 sin(x) cos(x) + cos^{2}(x)]$

$= \pi[1-2sin(x)cos(x)]$

$= \pi[1-sin(2x)]$

Now,

Integrate from $x=\frac{\pi}{4}\ \ \ to\ \ \ x=\frac{5\pi}{4}$ , we get volume:

$V=\int_{\frac{\pi}{4}}^{\frac{5\pi}{4}} \pi[1-sin(2x)]dx$

After integrate without limit we get

$V=\pi[x+\frac{cos2x}{2}]$

Now after putting the limit, we get

V = π²

Hence, the required volume of the solid = π²

3 0

3 years ago

Please help me solve this.

san4es73 [151]

the answer is x is equals to 2 or x is equal to -5 in the equation x square + 3x - 10 is equals to zero where after solving you get x square + 5 x - 2 x - 10 is equals to zero you factorise you get x (x + 5) - 2 (x + 5) is equal to zero then after solving x is equals to 2 or -5

4 0

1 year ago

Read 2 more answers

Suppose that a country of 72 million people about 3600 die from drowning each year. What is the percent chance that a person wil

Sloan [31]

Your answer is 0.003%

8 0

2 years ago