Answer:
The answer is the second one
Answer:
Step-by-step explanation:
The hypothesis is written as follows
For the null hypothesis,
µd ≤ 10
For the alternative hypothesis,
µ > 10
This is a right tailed test
Since no population standard deviation is given, the distribution is a student's t.
Since n = 97
Degrees of freedom, df = n - 1 = 97 - 1 = 96
t = (x - µ)/(s/√n)
Where
x = sample mean = 8.9
µ = population mean = 10
s = samples standard deviation = 3.6
t = (8.9 - 10)/(3.6/√97) = - 3
We would determine the p value using the t test calculator. It becomes
p = 0.00172
Since alpha, 0.01 > than the p value, 0.00172, then we would reject the null hypothesis. Therefore, At a 1% level of significance, there is enough evidence that the data do not support the vendor’s claim.
Because you if it changes its a function
Answer:
Step-by-step explanation:
4/5a*3/2a^2
4*3/5a*2a^2
12/10a^3
6/5a^3
therefore ur answer is 6/5a^3
