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3 years ago

find the equation of the line that has a slope of -1 and a y interception of -6 write your answer in y=mx+b form

Mathematics

1 answer:

Yakvenalex [24]3 years ago

8 0

Answer: y = -x - 6

Step-by-step explanation:

The equation of a line in slope-intercept form is given as :

y = mx + b , where m is the slope and b is the y - intercept.

From the question :

m = - 1

b = -6

substituting into the formula , we have

y = -1(x) - 6

y = -x - 6

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I have to turn that into the simplest form

zimovet [89]

$5.006=5\frac{6}{1000} =5\frac{3}{500}...or...\frac{2,503}{500}$

Hope this helps!

8 0

2 years ago

Read 2 more answers

Please help me now ! Thank you

jarptica [38.1K]

First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values

5 0

3 years ago

What product does the model show?

Karolina [17]

What model? It only says please help me lol

4 0

3 years ago

Read 2 more answers

XYZ has coordinates X(2, 3), Y(1,4), and Z(8,9). A translation maps X to X'(4,7). What are the coordinates for Y' and Z' for thi

Rashid [163]

Answer:

The coordinates are $Y'(x,y) = (3, 8)$ and $Z'(x,y) = (10, 13)$ .

Step-by-step explanation:

First, we have to derive an expression for translation under the assumption that each point of XYZ experiments the same translation. Vectorially speaking, translation from X to X' is defined by:

$X'(x,y) = X(x,y) + T(x,y)$ (1)

Where $T(x,y)$ is the vector translation.

If we know that $X(x,y) = (2,3)$ and $X'(x,y) = (4,7)$ , then the vector translation is:

$T(x,y) = X'(x,y)-X(x,y)$

$T(x,y) = (4,7) - (2,3)$

$T(x,y) = (2, 4)$

Then, we determine the coordinates for Y' and Z':

$Y'(x,y) = Y(x,y) + T(x,y)$

$Y'(x,y) = (1,4) + (2,4)$

$Y'(x,y) = (3, 8)$

$Z'(x,y) = Z(x,y) + T(x,y)$

$Z'(x,y) =(8,9) + (2,4)$

$Z'(x,y) = (10, 13)$

The coordinates are $Y'(x,y) = (3, 8)$ and $Z'(x,y) = (10, 13)$ .

7 0

2 years ago

Greg deposited $4000 into an account with 4.6% interest, compounded semiannually. Assuming that no withdrawals are made, how muc

Zinaida [17]

The amount in account after 7 years is $ 5499.445

Solution:

The formula for total amount in compound interest is given as:

$A = p(1+\frac{r}{n})^{nt}$

A = the future value of the investment/loan, including interest

P = the principal investment amount (the initial deposit or loan amount)

r = the annual interest rate (decimal)

n = the number of times that interest is compounded per unit t

t = the time the money is invested or borrowed for

Here given that,

A = ?

P = 4000

t = 7 years

$r = 4.6 \% = \frac{4.6}{100} = 0.046$

n = 2 ( since compounded semi annually)

Substituting the values in formula, we get

$A = 4000(1+\frac{0.046}{2})^{2 \times 7}\\\\Simplify\ the\ above\ expression\\\\A = 4000(1+0.023)^{14}\\\\A = 4000(1.023)^{14}\\\\A = 4000 \times 1.37486\\\\A = 5499.445$

Thus amount in account after 7 years is $ 5499.445

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3 years ago