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sattari [20]
3 years ago
14

A city planner makes a scale drawing of a proposed playground. The length of the actual playground is 78 feet, and the width is

42 feet. Suppose a scale of 0.5 inch = 6 feet is used. Which dimensions represent the playground on the scale drawing? A) 4.5 inches by 7 inches B) 6.5 inches by 3.5 inches C) 8 inches by 4 inches D) 9.2 inches by 5.5 inches
Mathematics
2 answers:
Otrada [13]3 years ago
7 0

Answer:   B)  6.5 inches by 3.5 inchesStep-by-step explanation:Multiplying the actual dimensions by the scale gives the scale dimensions:   (0.5 in)/(6 ft) × {78 ft, 42 ft}   = {39/6 in, 21/6 in}   = {6.5 in, 3.5 in}The size on the scale drawing is 6.5 inches by 3.5 inches.

Allushta [10]3 years ago
5 0

Answer:

  B)  6.5 inches by 3.5 inches

Step-by-step explanation:

Multiplying the actual dimensions by the scale gives the scale dimensions:

  (0.5 in)/(6 ft) × {78 ft, 42 ft}

  = {39/6 in, 21/6 in}

  = {6.5 in, 3.5 in}

The size on the scale drawing is 6.5 inches by 3.5 inches.

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weqwewe [10]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: x = 3

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:  log_{2}(x - 1)  log_{2}(x + 5)  = 4

\qquad \tt \rightarrow \:  log_{2} \{(x - 1)(x + 5) \} = 4

[ log (x) + log (y) = log (xy) ]

\qquad \tt \rightarrow \: ( x - 1)(x + 5) =  {2}^{4}

\qquad \tt \rightarrow \:  {x}^{2}  + 5x - x - 5 =  16

\qquad \tt \rightarrow \:  {x}^{2}  + 4x - 5 - 16 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 4x -21 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 7x - 3x - 21 = 0

\qquad \tt \rightarrow \:  x(x + 7) - 3(x + 7) = 0

\qquad \tt \rightarrow \: (x + 7)(x - 3) = 0

\qquad \tt \rightarrow \: x =  - 7 \:  \: or \:  \: x = 3

The only possible value of x is 3, since we can't operate logarithm with a negative integer in it.

\qquad \tt \rightarrow \: x = 3

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