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3 years ago

Approximately 3.24 billion gallons of water flow over niagra falls daily. concrete or discrete?

Mathematics

1 answer:

Naddika [18.5K]3 years ago

7 0

I think it is concrete.

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Where is mean by g(x)

matrenka [14]

Answer:

g(x)=2x or h(x) =2x,,,, mean the same thing

5 0

2 years ago

Kayla is building a custom frame using reclaimed wood. She needs the frame to be 14 1/2 inches wide by 9 1/4 inches long. She ha

Alborosie

She will have 6 and 1/4 inches of wood left. 23 3/4 - 30 is 6 1/4.

6 0

3 years ago

A two-factor between-subjects design is evaluated. The F-value for Factor A has df = 1, 40 and the F-value for Factor B has df =

finlep [7]

Answer:

The df values for the A x B interaction are also 3,40

Step-by-step explanation:

The F-value for Factor A has df = 1, 40

The F-value for Factor B has df = 3, 40.

The df values for the A x B interaction are also 3,40

This is because the source of variation between columns has ( c- 1); rc(n-1) degrees of freedom and the source of variation between rows has (r-1); rc(n-1) degrees of freedom and the source of variation of interaction

(between rows and columns) has ( c-1) ( r-1); rc(n-1) degrees of freedom.

Therefore

Factor A: ( c- 1); rc(n-1) = 1,40

<u>Factor B: (r-1); rc(n-1) = 3,40</u>

Interaction : ( c-1) ( r-1); rc(n-1) = 3*1,(40)= 3,40

where c refers to columns , r refers to rows and n refers to the total sample size.

5 0

3 years ago

So its 8p = 56 is the frist bit and the second is 7. BOOM

Mice21 [21]

p=7, I don't know if this is a question or not

7 0

3 years ago

A catering service offers 5 appetizers,4 main courses, and 8 desserts. A customer is to select 4 appetizers,2 main courses,and 3

Alisiya [41]

Answer:

468 ways

Step-by-step explanation:

Given: A catering service offers 5 appetizers, 4 main courses, and 8 desserts

To find: number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts.

Solution:

A permutation is an arrangement of elements such that order of elements matters and repetition is not allowed.

Number of appetizers = 5

Number of main courses = 4

Number of desserts = 8

Number of ways of choosing k terms from n terms = $nPk=\frac{n!}{(n-k)!}$

Number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts = $5P4+4P2+8P3$

$=\frac{5!}{(5-4)!}+\frac{4!}{(4-2)!}+\frac{81}{(8-3)!}\\=5!+\frac{4!}{2!}+\frac{8!}{5!}\\=5!+(4\times 3)+(8\times 7\times 6)\\=120+12+336\\=468$

So, this can be done in 468 ways.

7 0

3 years ago