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Irina18 [472]
3 years ago
7

Help me please I need this for tomorrow Questions:24,25,26 and 27 please and Godbless you

Mathematics
1 answer:
Whitepunk [10]3 years ago
7 0

24) -10 to 25 

25) 42

26) to much

27) also too much


don't get mad, this was only for 13 points so that's on you

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Fill in the blank to complete the calculation using the distributive property.
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Where’s the picture of the question or the blank?
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3 years ago
A lampshade has a height of 12cm and upper and lower diameters of 10cm and 20cm A)what area of material is required to cover tha
netineya [11]

Answer:

(a)\ Area = 195\pi

(b)\ Volume = 700\pi

Step-by-step explanation:

Given

h = 12

d_1 = 10 --- lower diameter

d_2 = 20 --- upper diameter

Solving (a): The curved surface area

This is calculated as:

Area = \pi l(r_1 + r_2)

Where

r_1 = 0.5 * d_1 = 0.5 * 10 = 5 --- lower radius

r_2 = 0.5 * d_2 = 0.5 * 20 = 10 --- upper radius

And

l = \sqrt{h^2 + (r_1 - r_2)^2 ---- l represents the slant height of the frustrum

l = \sqrt{12^2 + (5 - 10)^2

l = \sqrt{12^2 + (-5)^2

l = \sqrt{144 + 25

l = \sqrt{169

l = 13

So, we have:

Area = \pi l(r_1 + r_2)

Area = \pi * 13(5 + 10)

Area = \pi * 13(15)

Area = 195\pi

Solving (b): The volume

This is calculated as:

Volume = \frac{1}{3}\pi * h * (r_1^2 + r_2^2 + (r_1 * r_2))

This gives:

Volume = \frac{1}{3}\pi * 12 * (5^2 + 10^2 + (5 * 10))

Volume = \frac{1}{3}\pi * 12 * (25 + 100 + (50))

Volume = \frac{1}{3}\pi * 12 * (175)

Volume = \pi *4 * 175

Volume = 700\pi

6 0
3 years ago
Thomas needs to buy a cardboard sheet that will allow him to make his 224 in 3 box. To help construct the box, he decided to cut
Slav-nsk [51]

Answer:

Part 1; The volume of the box Thomas wants to make is 224 = 2·w² + 12·w

Part 2; The zeros for the equation of the function, are w = -14, or w = 8

Part 3

The width of the box is 8 inch

The length of the box, is 14 inches

The height of the box, is given as 2 inches

Part 4

Please find attached the graph of the function

Step-by-step explanation:

Part 1

The volume of the box Thomas wants to make, V = 224 in.³

The dimensions he cuts out from the length and width = 2 in² each

The length of the box = 6 inches + The width of the box

Let <em>l</em> represent the length of the box and let <em>w</em> represent the width of the box, we have;

l = 6 + w

The height of the box, h = The length of the cut out square = 2 inches

The volume of the box, V = Length, l × Width, w × Height, h

∴ V = l × w × h

l = 6 + w, h = 2

∴ V = (6 + w) × w × 2

V = 2·w² + 12·w,

The equation of the volume of the box, V = 2·w² + 12·w, where, V = 224

∴ 224 = 2·w² + 12·w

Part 2

The zeros of the equation for the volume of the box, V = 2·w² + 12·w, where, V = 224 are found as follows;

V = 224 = 2·w² + 12·w

∴ 2·w² + 12·w - 224 = 0

Dividing by 2 gives;

(2·w² + 12·w - 224)/2 = w² + 6·w - 112 = 0

∴ (w + 14) × (w - 8) = 0

The zeros for the equation of the function, are w = -14, or w = 8

Part 3

We reject the value, w = -14, therefore, the width of the box, w = 8 inch

The length of the box, l = 6 + w

∴ l = 6 + 8 = 14

The length of the box, l = 8 inches

The height of the box, <em>h</em>, is given as h = 2 inches

Part 4

The graph of the function created with MS Excel is attached

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3 years ago
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Answer: 1 1/6

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2 years ago
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