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oksano4ka [1.4K]
3 years ago
6

Which statements about g are true

Mathematics
1 answer:
Gre4nikov [31]3 years ago
6 0

Step-by-step explanation:

Considering the function

g\left(x\right)=x

Checking the statement A)

As

g\left(x\right)=x

Putting x = -5.7 in the function

g\left(-5.7\right)=-5.7

Rounded to the nearest 1 or  the Ones Place.

g\left(-5.7\right)=-6

But, original statement is g\left(-5.7\right)=-5.

So, the original statement is NOT TRUE.

Checking the statement B)

As

g\left(x\right)=x

Putting x = -2.3 in the function

g(-2.3) = -2.3

Rounded to the nearest 1 or  the Ones Place.

g(-2.3)=-2

As original statement is also  g(-2.3)=-2.

So, the original statement is TRUE.

Checking the statement C)

As

g\left(x\right)=x

Putting x = -0.6 in the function

g(-0.6) = -0.6

Rounded to the nearest 1 or  the Ones Place.

g(-0.6) = -1

As original statement is also g(-0.6) = -1  .

So, the original statement is TRUE.

Checking the statement D)

As

g\left(x\right)=x

Putting x = 4.1 in the function

g\left(4.1\right)=4.1

Rounded to the nearest 1 or  the Ones Place.

g\left(4.1\right)=4

But, original statement is g\left(4.1\right)=5.

So, the original statement is NOT TRUE.

Checking the statement E)

As

g\left(x\right)=x

Putting x = 7.5 in the function

g\left(7.5\right)=7.5

Rounded to the nearest 1 or  the Ones Place.

g\left(7.5\right)=8

But, original statement is g\left(7.5\right)=7

So, the original statement is NOT TRUE.

Keywords: function, Rounded to the nearest 1 or

the Ones Place

Learn more about function evaluation from brainly.com/question/11743679

#learnwithBrainly

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Andrej [43]

Answer:

a) Josef jogging from A to B;

i. speed = 2 m/s

ii. velocity = 2m/s

a) a) Josef jogging from A to C;

speed = 1.9 m/s

ii. velocity = 2.2 m/s

Step-by-step explanation:

One major difference between speed and velocity is that speed is a scalar quantity, while velocity is a vector quantity.

a) Josef jogging from A to B;

distance = 300 m

time = 2.5 seconds = 150 seconds

i. his average speed = \frac{distance}{time}

                               = \frac{300}{150}

                               = 2 m/s

ii. his average velocity = \frac{displacement}{time}

                               = \frac{300}{150}

                               = 2 m/s

b) Josef jogging from A to C,

distance = 300 + 100 = 400 m

time = 2.5 + 1 = 3.5 minutes

        = 210 seconds

i. his average speed = \frac{distance}{time}

                                  = \frac{400}{210}

                                  = 1.9 m/s

ii. his average velocity = \frac{\sqrt{V_{1} ^{2}   + V_{2} ^{2} } }{2}

V_{1} ^{2} = 4 m/s

V_{2} ^{2} = 1.9 m/s

his average velocity = \frac{\sqrt{4^{2} + 1.9^{2}  } }{2}

                                  = 2.2 m/s

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Answer:

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Step-by-step explanation:

Step 1. Find the slope

m = slope

m = change in y/change in x

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points: (2, -6) & (8, -2)

m = (-2 - -6)/(8 - 2)

m = 4/6

m = 2/3

Step 2. Create the point-slope equation by using the slope and the first point

Point-slope formula: y - y1 = m(x - x1)
Where m = slope and (x1, y1) = first point

Point-slope form: y + 6 = 2/3 (x - 2)

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