Name and give the abbreviation for the nucleic acid found mainly in the nucleus
1 answer:
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Answer:
K = 9.620 × 10⁻⁶
Explanation:
From the given information:
Temperature T= 6° C
= (273 + 6)K
= 279 K
The correct and well presentation of the reactions are:
1. ⇆ oxyluciferin + light ΔG₁°
2. ATP ⇄ AMP + PP ΔG₂° = -31.6 kJ/mol
The overall ΔG° = -4.80 kJ/mol
Let's first determine the ΔG₁° for the equation (1)
ΔG° = ΔG₁° + ΔG₂°
- ΔG₁° = - ΔG° + ΔG₂°
ΔG₁° = ΔG° - ΔG₂°
ΔG₁° = ( -4.80 - (-31.6) ) kJ/mol
ΔG₁° = 26.8 kJ/mol
Using the formula:
ΔG° = -RTIn K
K = antilog (-5.017)
K = 9.620 × 10⁻⁶