Identify whether each line is linear, quadratic, or neither

(x+2)(x2 - 2x+4)expand and simplify

Ksenya-84 [330]

Answer:

Step-by-step explanation:

2x2 is 4

5 0

3 years ago

Find the angle θ between u = <7, –2> and v = <–1, 2>.

Dmitry_Shevchenko [17]

The angle between two vectors is:

CosФ = u - v / Magnitude(u) x magnitude(v)

Magnitude of u = SQRT(7^2 + -2^2) = SQRT(49 +4) = SQRT(53)

Magnitude of v = SQRT(-1^2 +2^2) = SQRT(1 +4) = SQRT(5)

u x v = (7 x -1) + (-2 x 2) = -7 + -4 = -11

cosФ = -11 / sqrt(53) x sqrt(5)

cosФ = -11sqrt265) / 265

Ф =cos^-1(-11sqrt265) / 265)

Ф=132.51 degrees.

7 0

4 years ago

Read 2 more answers

if mya had 20 candy and ellie had 100000000000000000000000000 candy how many dose ellie and mya have togeather

jolli1 [7]

Answer:

100000000000000000000000020

Step-by-step explanation:

There you go

3 0

3 years ago

Read 2 more answers

The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,

professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so $\mu = 7*0.6 = 4.2$

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150$

$P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630$

$P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323$

So

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103$

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0

3 years ago

Please solve these four equations a) x/3=x+4 b) m-3=4/5m-2 c) x/5-4=2-2x/5 d) 1/2+w=8-3w/2

Ilia_Sergeevich [38]

I hope these help you

A)

x3=x+4Step 1: Simplify both sides of the equation.13x=x+4Step 2: Subtract x from both sides.13x−x=x+4−x−23x=4Step 3: Multiply both sides by 3/(-2).(3−2)*(−23x)=(3−2)*(4)x=−6Answer:x=−6

B)

m−3=45m−2Step 1: Subtract 4/5m from both sides.m−3−45m=45m−2−45m15m−3=−2Step 2: Add 3 to both sides.15m−3+3=−2+315m=1Step 3: Multiply both sides by 5.5*(15m)=(5)*(1)m=5Answer:m=5

C)

x5−4=2−2(x5)Step 1: Simplify both sides of the equation.x5−4=2−2(x5) Simplify: (Show steps) 15x−4=−25x+2Step 2: Add 2/5x to both sides.15x−4+25x=−25x+2+25x35x−4=2Step 3: Add 4 to both sides.35x−4+4=2+435x=6Step 4: Multiply both sides by 5/3.(53)*(35x)=(53)*(6)x=10Answer:x=10

D)

12+w=8−3(w2)Step 1: Simplify both sides of the equation.12+w=8−3(w2) Simplify: (Show steps) w+12=−32w+8Step 2: Add 3/2w to both sides.w+12+32w=−32w+8+32w52w+12=8Step 3: Subtract 1/2 from both sides.52w+12−12=8−1252w=152Step 4: Multiply both sides by 2/5.(25)*(52w)=(25)*(152)w=3Answer:w=3

4 0

3 years ago