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alexandr1967 [171]

3 years ago

5

What are the answers for questions 3&4? explanations if possible please!

1 answer:

kondor19780726 [428]3 years ago

6 0

For 3 you have to subtract 72 on both sides
+72 -2X=54
-72 -72
72-72 cancels out and then subtract the 54 from -72 the answer for that then should be divided by -2
and then X= (the answer)
and the -72 goes under 54 not -2x

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What is (99/100)^101 times (100/99)^100?

sineoko [7]

Answer:

99/100

Step-by-step explanation:

First of all recall that

$a^n\cdot b^n =(ab)^n$

Now we we will try to apply that formula for $a=99/100$ and $b=100/99$ .

First rewrite $(99/100)^{101}=(99/100)\times (99/100)^{100}$

Now

$(99/100)\times (99/100)^{100}\times (100/99)^{100}\\=(99/100)\times ((99/100)\times (100/99))^{100}\\=(99/100)\times 1^{100}\\=(99/100)\times 1\\=99/100$

7 0

3 years ago

Factors and common factors of 24,64,88

babunello [35]

24- 1,2,3,4,6,8,12,24
64-1,2,4,8,16,32,64
88-1,2,4,8,11,22,44,88

Here are all the factors.^^
The common factors are 1,2,3,4,6
Hope this helps!

8 0

3 years ago

What shape is this

suter [353]

Step-by-step explanation:

blank I don't see a shape

4 0

3 years ago

) The density of oil in a circular oil slick on the surface of the ocean at a distance of r meters from the center of the slick

Feliz [49]

Answer:

Therefore the mass of the of the oil is 409.59 kg.

Step-by-step explanation:

Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).

The area of the disk

=The area of the outer circle - The area of the inner circle

= $\pi (r+\triangle r)^2- \pi r^2$

$=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]$

$=\pi [2r\triangle r+(\triangle r)^2]$

Since (Δr)² is very small, So it is ignorable.

∴ $A=2\pi r\triangle r$

The density $\delta (r)= \frac{40}{1+r^2}$

We know,

Mass= Area× density

$=(2r \pi \triangle r)(\frac{40}{1+r^2}})$

Total mass $M=\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i$

Therefore

$\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i=\int_0^5 \frac{80r\pi }{1+r^2}dr$

$=40\pi[ln(1+r^2)]_0^5$

$=40\pi [ln(1+5^2)-ln(1+0^2)]$

$=40\pi ln(26)$

= 409.59 kg (approx)

Therefore the mass of the of the oil is 409.59 kg.

3 0

2 years ago

n Juanita's Art History class Quizzes are worth 15% of the final grade, Exams are worth 55%, Projects are worth 25%, and Attenda

kvv77 [185]

Answer:

90.75%

Step-by-step explanation:

Given;

Of the total final score;

Quizzes = 15%

Exam = 55%

Project = 25%

Attendance = 5%

Resolving the values of each section of the total score;

she had perfect attendance to class. 100% attendance;

Attendance = 5% of total score

She got extra credit on her project with a score of 26 out of 25 possible points.

Project = 26/25 × 25% = 26%

80, 85, and 96 on the first three exams,each worth 100 points;

Total exam score = 80+85+96 = 261 out of 300

Of the total score;

Exam = 261/300 × 55% = 47.85%

At mid-semester Juanita scored 119 out of 150 points on quizzes.

Quizzes = 119/150 × 15% = 11.9%

Total exam score is;

= Quizzes+exam +project+attendance

= 11.9% + 47.85% + 26% + 5%

= 90.75%

3 0

2 years ago