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qaws [65]
3 years ago
8

Theodore works for Mr. Jones. Mr. Jones agreed to start Theodore at $.01 the first day, $.02 the second day, $.04 the third day,

$.08 the fourth day, and so on.
`
a. How much does Theodore earn in fifteen days?

b. Suppose Theodore can start at $10 the first day, $10.75 the second day, $11.50 the third day, $12.25 the fourth day, and so on. Would he earn more in fifteen days than he does in part(a)? Explain.
Mathematics
1 answer:
Studentka2010 [4]3 years ago
7 0
Well, it looks like the amount increases by x2.
So just multiply by 2 until day 15

Day 4: 0.8
0.8 x 2 = 0.16
Day 5: 0.16
0.16 x 2 = 0.32
Day 6: 0.32
From here you should know what to do and I'll skip the long math
Day 15: 163.84

============================================================
Part B
The difference in change for these number is about x1.07 so multiply by 1.07 till day 15.
Again I'll avoid the extra long math
Day 15: 25.78
He would not earn more in 15 days than part a
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Answer:  11

Step-by-step explanation:

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x

 

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60

​  

=  

550

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​  

 

Divide both sides by 550

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\log 0.109091=\log 0.812^x

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Take the log of both sides

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use power rule to bring x to the front

\frac{\log 0.109091}{\log 0.812}=\frac{x\log 0.812}{\log 0.812}

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log0.109091

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=  

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xlog0.812

​  

 

Divide both sides by log(0.812)

10.638757=x

10.638757=x

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