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marshall27 [118]
3 years ago
14

Help solve the above equation ​

Mathematics
1 answer:
Tresset [83]3 years ago
5 0

Answer:

\dfrac{1}{27}

Step-by-step explanation:

n^{-\frac{2}{3}}=9

Rewrite:

\dfrac{1}{\sqrt[3]{n^2}}=9\\\\9\sqrt[3]{n^2}=1

Cube both sides:

729n^2=1

Divide both sides by 729:

n^2=\dfrac{1}{729}

Take the square root of both sides:

n=\sqrt{\dfrac{1}{729}}=\dfrac{1}{27}

Hope this helps!

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