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murzikaleks [220]
3 years ago
10

What is the probability of getting heads when flipping a coin and getting a number greater than or equal to 4 when rolling a sin

gle die?
Mathematics
2 answers:
lbvjy [14]3 years ago
5 0
"Assuming a fair coin<span> and a fair 6-sided </span>die<span>. </span>Coin<span> has 2 sides with </span>equal probability<span>, 50% each. </span>Die<span> has 6 sides with </span>equal probability<span>, 1/6 odds </span>for<span> each side. ... The</span>probability of getting heads<span> is 1/2, and the </span>probability of getting<span> 5 or 6 is 1/3, and so you simply multiply 1/2 x 1/3, which is 1/6."</span>
Sedaia [141]3 years ago
5 0

Answer's 1/4 in APEX

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Carl saved $22 in the last 3 weeks.<br> About how much will he save after 20<br> weeks?
olga_2 [115]

22 / 3 = 7.3333

7.3333 * 20 = 146.67

$146.67

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Find the common difference of the sequence shown.
larisa86 [58]

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1/6

Step-by-step explanation:

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Suppose a Pony Express rider was paid $192 for 12 weeks of work. If he was paid the same amount each week,how much was he paid f
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$192 divided by 12 is 16 so 16 x 3 is 48. That is your answer $48. Your welcome bud.
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3 years ago
What should I buy? A study conducted by a research group in a recent year reported that of cell phone owners used their phones i
Llana [10]

Answer:

The probability that seven or more of them used their phones for guidance on purchasing decisions is 0.7886.

<em />

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>What should I buy? A study conducted by a research group in a recent year reported that 57% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 14 cell phone owners is studied. Round the answers to at least four decimal places. What is the probability that seven or more of them used their phones for guidance on purchasing decisions? </em>

We can model this as a binomial random variable, with p=0.57 and n=14.

P(x=k)=\dbinom{n}{k} p^{k}q^{n-k}

a) We have to calculate the probability that seven or more of them used their phones for guidance on purchasing decisions:

P(x\geq7)=\sum_{k=7}^{14}P(x=k)\\\\\\

P(x=7)=\dbinom{14}{7} p^{7}q^{7}=3432*0.0195*0.0027=0.1824\\\\\\P(x=8) = \dbinom{14}{8} p^{8}q^{6}=3003*0.0111*0.0063=0.2115\\\\\\P(x=9) = \dbinom{14}{9} p^{9}q^{5}=2002*0.0064*0.0147=0.1869\\\\\\P(x=10) = \dbinom{14}{10} p^{10}q^{4}=1001*0.0036*0.0342=0.1239\\\\\\P(x=11) = \dbinom{14}{11} p^{11}q^{3}=364*0.0021*0.0795=0.0597\\\\\\P(x=12) = \dbinom{14}{12} p^{12}q^{2}=91*0.0012*0.1849=0.0198\\\\\\P(x=13) = \dbinom{14}{13} p^{13}q^{1}=14*0.0007*0.43=0.004\\\\\\

P(x=14) = \dbinom{14}{14} p^{14}q^{0}=1*0.0004*1=0.0004\\\\\\

P(x\geq7)=0.1824+0.2115+0.1869+0.1239+0.0597+0.0198+0.004+0.0004\\\\P(x\geq7)=0.7886

7 0
3 years ago
Which expression is equivalent to the expression shown?
choli [55]
<h3>Answer: 5^24</h3>

<h2>Maybe it can be your answer but i am not sure that it is fixed answer </h2>
5 0
3 years ago
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