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katrin2010 [14]
3 years ago
7

A hardware store sells rope at a fixed price per foot. A 50-foot piece of rope cost $12. Write an equation that relates C, the c

ost in dollars of a piece of rope, to f, the length in feet of the piece of rope.
Mathematics
1 answer:
Masja [62]3 years ago
8 0
C=6/25f
6/25 is the cost per foot
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Francine ran 3 1/2 laps around the circular track in the school gym. The track has a diameter of 1/2 miles. About how far does F
Juliette [100K]

Answer:

Francine run 5.495 miles

Step-by-step explanation:

Given :

Francine ran  3\frac{1}{2}  laps around the circular track in the school gym.

The track has a diameter of 1/2 miles.

To Find :  About how far does Francine run?

Solution :

First we need to calculate the perimeter of circular track :

Perimeter of circle :  2\pi r

Since we are given the diameter = 1/2 miles = 0.5 miles

So, Radius will be (Diameter/2) = 0.5/2 = 0.25 miles

So, The perimeter will be:

2\pi *0.25

0.5\pi

Since \pi =3.14

⇒0.5*3.14

⇒1.57

Thus the circular track is of 1.57 miles .

Since she ran   3\frac{1}{2}  = 7/2=3.5 laps

1 lap = 1.57 miles

So, 3.5 laps = 1.57*3.5 =5.495 miles .

Hence ,  Francine run 5.495 miles


6 0
3 years ago
Line L passes through the points (0 - 3) and (6,9).
Luden [163]

a)  find the slope of the line using the given points.

Slope:  9 - -3/6-0 then slope is 12/6 which is 2

Then using formula:  y = mx+b

-3 = 2(0) + b

b = -3

The equation is:  y = 2x -3

B. Slope of a perpendicular is -reciprocal of first line. So here the slope will be -1/2

y = mx + b is used again

2 = -1/2(0) + b

b = 2

The equation is:  y = -1/2x +2

4 0
3 years ago
What are the points of intersection of -x^2+9x-3 and y=3x
ELEN [110]

Answer:

Easiest and fastest way is to graph both equations into a graphing calc and trace the graph to where they intersect.

Alternatively, you can use substitution to solve for your answer.

Step-by-step explanation:

8 0
3 years ago
In parallelogram QRST QS RT Is QRST a rectangle ?
fomenos

Answer:

The correct option is A.

Step-by-step explanation:

It is given that the QRST is a parallelogram and the diagonals QS and RT are congruent.

According to the property of parallelogram if the length of diagonals are same, then the parallelogram is rectangle. We can also prove it.

Let QRST be an parallelogram and QS=RT.

In triangles QRT and RQS.

RT=QS         (Diagonals)

QR=QR         (Common side)

QT=RS         (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QRT and triangle RQS are congruent.

By CPCT,

\angle R=\angle Q

Since the sum of two consecutive angles of a parallelogram is 180 degree.

\angle R+\angle Q=180

2\angle R=180

\angle R=90

Therefore the measure of angle R and angle Q are 90 degree.

Similarly in triangle QST and RTS,

RT=QS         (Diagonals)

ST=ST         (Common side)

QT=RS         (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QST and RTS are congruent.

By CPCT,

\angle S=\angle T

Since the sum of two consecutive angles of a parallelogram is 180 degree.

Therefore the measure of angle S and angle T are 90 degree.

Since the measure of all interior angles of QRST are 90 degree, therefore the parallelogram QRST  is a rectangle.

6 0
3 years ago
Read 2 more answers
What is the answer to 2/5x+3/7=1-4/7x
skelet666 [1.2K]
X=10/17 thats ur answer

7 0
3 years ago
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