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mr_godi [17]
3 years ago
6

Three consecutive even integers have a sum of -126. What is the smallest integer ?

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
5 0

Answer:

-40, - 42 and -44

Step-by-step explanation:

The fastes way here is trying. Lets pick a number, intelligently, and then work on it.

We need three even integers that sum -126. These will be all negative numbers and as they are consecutive they will be very similar (for example, -33 and -35 and -37). Thus, lets start by 1/3 of -126, which is -42:

(-42)+ (-44) + (-46) = - 132, so -42 no.

Lets go a step back: -40

(-40) + (-42) + (-44) = -126

So, the integers are -40, -42 and -44

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AVprozaik [17]
FIRST SOLUTION!
first number = x
second number = x+2
third number = x+4
fourth number=x+6
fifth number=x+8
sixth number=x+10
seventh number=x+12

add all of those up and combine like terms to get 7x+42=357. Now subtract 42 from both sides to get 7x=315. Next, divide both sides by 7 to get x=45. To get the numbers, plug in 45 for x.

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