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SVEN [57.7K]
3 years ago
7

-5x+7x+8=1+3x im am looking for what makes this equation true

Mathematics
1 answer:
zvonat [6]3 years ago
6 0

Answer:

<em>x=7</em>

Step-by-step explanation:

Start with the left side

-5x+7x+8

combine like terms

2x+8=1+3x

subtract 2x from both sides to get 8=1+x

subtract 1 from both sides to get 7

put the variable on the left

<em>x=7</em>

<u>Hope this helps :-)</u>

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# 6
zhuklara [117]

9514 1404 393

Answer:

  y = 5x - 7

Step-by-step explanation:

We can make an equation for the perpendicular line by swapping the x- and y-coefficients, negating one of them. Then we can use that form with the given point to see what the constant is.

  10x -2y = ...

Removing a common factor of 2 gives ...

  5x -y = 5(2) -(3) = 7 . . . .  using (x, y) = (2, 3), we can find the constant

Solving for y, we get ...

  5x -7 = y . . . add y-7

  y = 5x -7 . . . write in the desired form

5 0
3 years ago
For the equation : y = 2x + 10. Write any two possible solutions in ordered form. (Hint: e.G ( 4, 18))
nalin [4]

Answer:

(0, 10)

and

(1, 12)

5 0
3 years ago
Read 2 more answers
Drummer and a guitarist each wrote songs for their band. The guitarist wrote 8 fewer than
vfiekz [6]

Answer:

g = 2d - 8

g + d = 46

6 0
3 years ago
PLSSS HELP IMMA FAIL
Nutka1998 [239]

Answer:

x = 10

Step-by-step explanation:

X = 10 because if you look at the 28 and 14, 14 is half of 28 so the ratio is 1:2 which would also work for the 20 so the answer is 10

4 0
3 years ago
I need help with this math question
ICE Princess25 [194]

Answer:

B. 5

Step-by-step explanation:

Step 1: Rewrite the equation a bit

\frac{7^\frac{3}{4}}{7^\frac{x}{8}}=\sqrt[8]{7}\\7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}

Step 2: Place a logarithm base 7 on both sides

7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}\\log_77^\frac{3}{4}^-^\frac{x}{8}=log_77^\frac{1}{8}\\(\frac{3}{4}-\frac{x}{8})log_77=\frac{1}{8}log_77\\(\frac{3}{4}-\frac{x}{8})1=\frac{1}{8}1\\\frac{3}{4}-\frac{x}{8}=\frac{1}{8}

Step 3: Solve for x

\frac{3}{4}-\frac{x}{8}=\frac{1}{8}\\\frac{6}{8}-\frac{x}{8}=\frac{1}{8}\\-\frac{x}{8}=-\frac{5}{8}\\\frac{x}{8}=\frac{5}{8}\\x=5

Neat exponent question :)

7 0
2 years ago
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