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Vlad1618 [11]
3 years ago
7

Which of the following describes the electron sharing between hydrogen and fluorine?

Chemistry
1 answer:
Naily [24]3 years ago
3 0
Since hydrogen only has 1 electron it shares 1 with flourine to have a pair. It is single bonded.
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What is the conversion of 160g to cg??
Umnica [9.8K]
16000
is the answer
because I used the calculater
3 0
3 years ago
Element Q is a theoretical nonmetal with atomic number 59. Consider the isotope: Q-95. How many electrons are in an atom of Q-95
Vinil7 [7]

60

Explanation:

The number of electrons in an atom of Q-95 will be 60 electrons.

The atomic number of an atom is the number of protons in the atom of the isotope

This number is unique to every atom and their isotope

An isotope of an atom is the existence of an atom having the same atomic number but different mass numbers.

Since atomic number the same as number of protons, they are the positively charged particles in an atom.

To have a negative charge, the number of electrons must be more than that of protons.

Charge = number of protons - number electrons

  charge = -1

  -1 = 59  - number of electrons

  Number of electrons = 60 electrons

learn more:

Number of subatomic particles brainly.com/question/2757829

#learnwithBrainly

4 0
3 years ago
What’s the formula equation for
jeyben [28]
If you have a magnesium for every oxygen, then you have to start with two magnesiums. So the balanced equation is 2 Mg + O2 2 MgO.

And

CaCO3———→CaO + CO2

I hope it helped!

7 0
3 years ago
Read 2 more answers
En el enlace covalente entre azufre y carbono (6 y 4 electrones en su ultima capa respectivamente) la molécula tendrá ?
d1i1m1o1n [39]

Answer:

a- Uno de carbono y dos de azufre

Explanation:

El compuesto formado entre el carbono y el azufre es CS2.

El carbono forma dos enlaces dobles con dos átomos de azufre.

Por lo tanto, el compuesto contiene un átomo de carbono y dos átomos de azufre.

6 0
3 years ago
The normal freezing point of a certain liquid
slavikrds [6]

Answer : The molal freezing point depression constant of liquid X is, 4.12^oC/m

Explanation :  Given,

Mass of urea (solute) = 5.90 g

Mass of liquid X (solvent) = 450 g  = 0.450 kg

Molar mass of urea = 60 g/mole

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of urea}}{\text{Molar mass of urea}\times \text{Mass of liquid X Kg}}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution = -0.5^oC

\Delta T^o = freezing point of liquid X = 0.4^oC

i = Van't Hoff factor = 1 (for non-electrolyte)

K_f = Molal-freezing-point-depression constant = ?

m = molality

Now put all the given values in this formula, we get

0.4^oC-(-0.5^oC)=1\times K_f\times \frac{5.90g}{60g/mol\times 0.450kg}

K_f=4.12^oC/m

Therefore, the molal freezing point depression constant of liquid X is, 4.12^oC/m

3 0
3 years ago
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