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iren [92.7K]
3 years ago
15

What is “ location of the sweat glands “

Chemistry
1 answer:
kompoz [17]3 years ago
8 0
Mostly found on the soles of feet, palms, forehead, cheeks and of course armpits they're also called eccrine sweat glands
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Which of the following describes a Brønsted-Lowry base?
Mice21 [21]
__ Brainliest if helped! 

Bronsted-Lowry definition of Bases are Proton acceptors, 

or i.e. "A hydrogen ion acceptor" 

4 0
3 years ago
Read 2 more answers
What measurements are used to calculate the density of a given object?
professor190 [17]

Answer:

Density = \frac{Mass}{Volume}

Explanation:

Density equals mass divided by volume.

Density often has units of grams per cubic centimeter (g/cm3). Remember, grams is a mass and cubic centimeters is a volume (the same volume as 1 milliliter).

8 0
3 years ago
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Hippuric acid (HC9H8NO3)(HC9H8NO3), found in horse urine, has pKa=3.62pKa=3.62. Part A Calculate the pHpH in 0.140 MM hippuric a
Oxana [17]

Answer:

The pH in 0.140 M hippuric acid solution is 2.2.

Explanation :

Dissociation constant of the acid = K_a

pK_a=-\log[K_a]

3.62=-\log[K_a]

K_a=2.399\times 10^{-4}

Concentration of hippuric acid = c = 0.140 M

HC_9H_8NO_3\rightleftharpoons C_9H_8NO_{3}^-+H^+

Initially

c           0     0

At equilibrium

(c-x)     x      x

Concentration of acid = c [HC_9H_8NO_3]=0.140 M

Dissociation constant of an acid is given by:

K_a=\frac{[C_9H_8NO_{3}^-][H^+]}{[HC_9H_8NO_{3}]}

K_a=\frac{x\times x}{(c -x)}

2.399\times 10^{-4}=\frac{x\times x}{(0.140 -x)}

Solving for x:

x = 0.005677 M

[H^+]=x = 0.005677 M

The pH of the solution :

pH=-\log[H^+]

pH=-\log[0.005677 M]=2.246\approx 2.2

The pH in 0.140 M hippuric acid solution is 2.2.

6 0
4 years ago
If i were to put cesium in water and francium in a tub of water which one would explode first?
hoa [83]
Well according to me Cesium releases enough energy that even a small piece blows up in water. Francium is below cesium on the table and would react more readily and violently.
4 0
3 years ago
1. The equation for the reaction between zinc and aqueous copper(II) sulfate is shown.
Fed [463]

Answer:

The oxidation state of the reducing agent has changed from 0 to +2.

Explanation:

reducing agent is anything that loses electron or gains oxygen

in this case, zinc

3 0
3 years ago
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