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Alexxandr [17]
3 years ago
7

Classify..use the periodic table to classify the elements potassium, bromine a d argon according to how likely their atoms lose

electrons to form positive ions
Chemistry
1 answer:
iren2701 [21]3 years ago
6 0

Answer:

Classification will be Potassium, Bromine, and Argon

Explanation:

  • Potassium is more likely to lose electrons and form positive ion
  • Bromine actually gain electrons and forms negative ion
  • Argon does not lose or gain electrons
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What happens to the energy level of particles when melting occurs
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Answer:

Melting occurs when a solid is heated and turns to liquid. The particles in a solid gain enough energy to overcome the bonding forces holding them firmly in place. Typically, during melting, the particles start to move about, staying close to their neighboring particles, then move more freely.

Explanation:

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According to Boyle’s law, when the pressure of a gas increases at constant temperature, its volume
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Answer:

reduces

Explanation:

According to Boyle's law, when the pressure of a gas increases at constant temperature the volume reduces.

Boyle's law states that "the volume of fixed mass of a gas is inversely proportional to the change in pressure if the temperature is constant".

  • It suggests that at constant temperature, if pressure increases, temperature reduces.

Mathematically, it is expressed as;

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P and V are pressures

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Phosphoric acid (h3po4) is tribasic, with pka's of 2.14, 6.86, and 12.4. The charge of the ionic form that predominates at ph 3.
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Correct answer is H_2PO_4^-.

Phosphoric acid is a polyprotic acid having 3 acidic hyrdogen therefore it will have 3 pka values.

The equations for the release of acidic hydrogen can be written as:

\\H_3PO_4\rightleftharpoons H_2PO_4^-+H^+\text{ pka=2.14}\\H_2PO_4^-\rightleftharpoons HPO_4^2^-+H^+\text{ pka=6.86}\\HPO_4^2^-\rightleftharpoons PO_4^3^-+H^+\text{ pka=12.4}

From the pka values we can judge the idea of pH as using Henderson-Hasselbalch Equation, we get the relation between pH and pka.

HA\rightarrow H^-+A^-

Using the following equation, relation of pH and pka is

pH=pka+log\frac{[A^-]}{HA}

Using this equation, we can find that the equation having pka= 2. 14 is closest to the pH=3.2 so the ionic form in this equation will be dominant at the same pH.

Therefore at pH=3.2 the ionic form H_2PO_4^- of H_3PO_4 is dominant.


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