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Alexxandr [17]
3 years ago
7

Classify..use the periodic table to classify the elements potassium, bromine a d argon according to how likely their atoms lose

electrons to form positive ions
Chemistry
1 answer:
iren2701 [21]3 years ago
6 0

Answer:

Classification will be Potassium, Bromine, and Argon

Explanation:

  • Potassium is more likely to lose electrons and form positive ion
  • Bromine actually gain electrons and forms negative ion
  • Argon does not lose or gain electrons
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Describe the factors which make an organism living
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3 years ago
Select True or False: A "gas" is a substance in which the molecules are separated on the average by distances that are large com
marta [7]

Answer:

True

Explanation:

The gaseous state is characterized in that the cohesion forces are usually null, in which the particles have their maximum mobility. The particles tend to occupy all the available volume, so their shape and volume are variable. The gaseous state is a dispersed state of matter, which means that the molecules are separated by distances much larger than the diameter of the gas molecules.

5 0
2 years ago
What volume (L) of 0.250 M HNO3 is required to neutralize a solution prepared by dissolving 17.5 g of NaOH in 350 mL of water ?
IRINA_888 [86]
<h3>Answer:</h3>

1.75 L HNO₃

<h3>Explanation:</h3>

We are given;

Molarity of HNO₃ as 0.250 M

Mass of NaOH as 17.5 g

Volume of NaOH = 350 mL

We are required to calculate the volume of 0.250 M

We are going to first write the balanced reaction:

NaOH(aq) + HNO₃(aq) → NaNO₃(aq) + H₂O(l)

Then, we calculate the number of moles of NaOH

Moles = Mass ÷ Molar mass

Molar mass of NaOH = 39.997 g/mol

          = 17.5 g ÷ 39.997 g/mol

          = 0.4375 moles

We can now calculate the number of moles of HNO₃ using the mole ratio from the equation;

Mole ratio of NaOH to HNO₃ is 1 : 1

Therefore, if moles of NaOH are 0.4375 moles then;

Moles of HNO₃ will also be 0.4375 moles

We can now calculate the volume of HNO₃

Morality = Number of moles ÷ Volume

Thus;

Volume = Number of moles ÷ Molarity

             = 0.4375 moles ÷ 0.250 M

             = 1.75 L

Therefore, the volume of HNO₃ is 1.75 L

5 0
3 years ago
Construct a simulated 1H NMR spectrum for ethyl acetate by dragging and dropping the appropriate splitting patterns into the box
Ksju [112]

Answer:

The simulated 1H NMR spectrum for ethyl acetate is shown in the drawing attached.

Explanation:

To construct this NMR it is necessary to identify the essential components that can produce resonance peaks.

Two main groups can be identified, the acetyl group containing a sub-component (CH3) capable of producing a resonance peak, and the ethyl group containing two components (CH2 and CH3) each of which can produce on its own its own resonance peak.

6 0
3 years ago
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