Answer:
b
Step-by-step explanation:
b
![\frac{22}{5} = 4 \frac{2}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B22%7D%7B5%7D%20%20%3D%204%20%5Cfrac%7B2%7D%7B5%7D%20%20)
$4.40
2 ÷ 5= 2/5 = .4 pounds or 2/5 of a pound per friend
Answer:
The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days
P(X≤ 0.11) = 0.4404
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 0.10 inches
Given that the standard deviation of the population = 0.07inches
Let 'X' be a random variable in a normal distribution
![Z = \frac{x-mean}{S.D} = \frac{0.11-0.10}{0.07} = 0.1428](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7Bx-mean%7D%7BS.D%7D%20%3D%20%5Cfrac%7B0.11-0.10%7D%7B0.07%7D%20%3D%200.1428)
<u><em>Step(ii):-</em></u>
The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days
P(X≤ 0.11) = P(Z≤0.1428)
= 1-P(Z≥0.1428)
= 1 - ( 0.5 +A(0.1428)
= 0.5 - A(0.1428)
= 0.5 -0.0596
= 0.4404
<u><em>Final answer:-</em></u>
The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days
P(X≤ 0.11) = 0.4404