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xxTIMURxx [149]
3 years ago
11

title="7 {x}^{3} + 4x - 5 + 8 {x}^{5} " alt="7 {x}^{3} + 4x - 5 + 8 {x}^{5} " align="absmiddle" class="latex-formula">
What is the degree of the polynomial?

A. 0
B. 1
C. 3
D. 5​
Mathematics
1 answer:
elixir [45]3 years ago
3 0

Answer:

D

Step-by-step explanation:

The degree of a polynomial is determined by the largest exponent of a term within the polynomial.

Given

7x³ + 4x - 5 + 8x^{5}

The term with the largest exponent is 8x^{5} with exponent 5

Thus the polynomial is of degree 5 → D

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Increase 840 in the ratio 2 : 3​
Iteru [2.4K]

Ratios be 2x and 3x

\\ \rm\longmapsto 2x+3x=840

\\ \rm\longmapsto 5x=840

\\ \rm\longmapsto x=\dfrac{840}{5}

\\ \rm\longmapsto x=168

Now

  • 2x=2(168)=336
  • 3x=3(168)=508
3 0
3 years ago
Read 2 more answers
PLZ HELP NOW I WILL GIVE BRAINLIEST!
solmaris [256]

Answer:

TSA=6a²

TSA=6*17*17=1734 mm²

Step-by-step explanation:

6 0
3 years ago
Need help asappp
lozanna [386]

Answer:

552

Step-by-step explanation:

4 0
3 years ago
Can someone please explain how to get the answer I've watched multiple videos on implicit derivatives and I still cant figure it
Arisa [49]

We're given the implicit equation

x² + 2x + y² - 4y = 12

where "implicit" means that one of the variables is considered a function of the other. In this case, the variable y = y(x) depends on the value of the variable x - in other words, the possible values of y are implied by the value of x. We then say that this equation defines y as an implicit function of x.

We're also given the implicit derivative,

dy/dx = (-2x - 2)/(2y - 4)

which tells us the rate of change y as a function of both x and y. The value of dy/dx corresponds to the slope of the tangent line to the curve defined by the implicit equation above at some point (x, y).

The tangent line is horizontal when its slope is zero. This happens when

(-2x - 2)/(2y - 4) = 0

If y ≠ 2, then we can eliminate the denominator and we're left with

-2x - 2 = 0

Solve for x :

-2x = 2

x = -1

This tells us that the points on the curve with x-coordinate -1 have a tangent line to the curve that is horizontal.

The tangent line is vertical when its slope is undefined/infinite, or equivalently when the denominator of dy/dx is zero:

2y - 4 = 0

Solve for y :

2y = 4

y = 2

So any point on the curve with y-coordinate 2 will have a tangent line there that is vertical.

By completing the square in the implicit equation, we can easily identify where these points are located.

x² + 2x + y² - 4y = 12

x² + 2x + 1 + y² - 4y + 4 = 17

(x + 1)² + (y - 2)² = 17

This equation defines a circle centered at (-1, 2) with radius √17. When x = -1, we have

(y - 2)² = 17   ⇒   y = 2 ± √17

and when y = 2, we have

(x + 1)² = 17   ⇒   x = -1 ± √17

See the attached plot to see the circle and the tangents at these points.

7 0
2 years ago
Circumference of a circle with radius 10 in
azamat
2*pi*10=62.83 is certainly your answer
5 0
2 years ago
Read 2 more answers
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