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ozzi
3 years ago
12

A spider ate 25%, more bugs this month than last month. the spider ate 888 bugs last month

Mathematics
2 answers:
HACTEHA [7]3 years ago
4 0

Answer: the spider eat  1110 bugs this month.

Step-by-step explanation:

multiply 888 * 25%   to find the increase amount of bugs that the spider ate this month.

888 * 25% = 222

Now add 222 to the number of bugs the spider ate last month

888 + 222 = 1110

tresset_1 [31]3 years ago
3 0

Answer:

1110 BUGS

Step-by-step explanation:

100%=888 BUGS

125%=X

125% X 888 BUGS=111000/100=1110

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Michael's dad is 30 years of age. He is 2 years more than four times Michaels age m. Write and solve a two-step equation to dete
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Answer:

The two step equation that we can use to find michael's age is x = (f-2)/4 where f = 30. So Michael is 7 years old.

Step-by-step explanation:

In order to solve this problem we will attribute variables to the ages of Michael and his father. For his father age we will attribute a variable called "f" and for Michael's age we will attribute a variable called "x". The first information that the problem gives us is that Michael's dad is 30 years of age, so we have:

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Distance=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}} \\

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The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than A(t)=A_{0}e^{kt}. for example, if an initial population P₀ requires n units of time to triple, then the function P(t)=P_{0}(3)^{\frac{t}{n} } models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form P(t)=P_{0}(3)^{\frac{t}{n} } that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form A(t)=A_{0}e^{kt}.

Answer: a) P(t)=50(3)^{\frac{t}{30} }

              b) P(t) = 280 insects

              c) t = 74 days

             d) A(t)=50e^{0.037t}

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

P(t)=50(3)^{\frac{t}{30} }

b) In t = 47 days:

P(t)=50(3)^{\frac{t}{30} }

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c) P(t) = 750

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Use Power Rule again:

ln3=ln(e^{30k})

ln3=30k

k=\frac{ln3}{30}

k = 0.037

Equation for exponential growth will be:

A(t)=50e^{0.037t}

3 0
3 years ago
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